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ajax調(diào)用返回php接口返回json數(shù)據(jù)的方法(必看篇)

更新時間：2017年05月05日 09:23:11 投稿：jingxian

下面小編就為大家?guī)硪黄猘jax調(diào)用返回php接口返回json數(shù)據(jù)的方法(必看篇)。小編覺得挺不錯的，現(xiàn)在就分享給大家，也給大家做個參考。一起跟隨小編過來看看吧

php代碼如下：

<?php

  header('Content-Type: application/json');
  header('Content-Type: text/html;charset=utf-8');

  $email = $_GET['email'];

  $user = [];

  $conn = @mysql_connect("localhost","Test","123456") or die("Failed in connecting database");
  mysql_select_db("Test",$conn);
  mysql_query("set names 'UTF-8'");
  $query = "select * from UserInformation where email = '".$email."'";
  $result = mysql_query($query);
  if (null == ($row = mysql_fetch_array($result))) {
    echo $_GET['callback']."(no such user)";
  } else {
    $user['email'] = $email;
    $user['nickname'] = $row['nickname'];
    $user['portrait'] = $row['portrait'];
    echo $_GET['callback']."(".json_encode($user).")";
  }

?>

js代碼如下：

<script>
    $.ajax({
      url: "http://test.localhost/UserInterfaceForChatroom/UserInformation.php?email=pshuyue@gmail.com",
      type: "GET",
      dataType: 'jsonp',
      //      crossDomain: true,
      success: function (result) {
        //        data = $.parseJSON(result);
        //        alert(data.nickname);
        alert(result.nickname);
      }
    });
  </script>

其中遇到了兩個問題：

1、第一個問題：

Uncaught SyntaxError: Unexpected token :

解決方案如下：

This has just happened to me, and the reason was none of the reasons above. I was using the jQuery command getJSON and adding callback=? to use JSONP (as I needed to go cross-domain), and returning the JSON code {"foo":"bar"} and getting the error.

This is because I should have included the callback data, something like jQuery17209314005577471107_1335958194322({"foo":"bar"})

Here is the PHP code I used to achieve this, which degrades if JSON (without a callback) is used:

$ret['foo'] = "bar";
finish();

function finish() {
  header("content-type:application/json");
  if ($_GET['callback']) {
    print $_GET['callback']."(";
  }
  print json_encode($GLOBALS['ret']);
  if ($_GET['callback']) {
    print ")";
  }
  exit; 
}

Hopefully that will help someone in the future.

2、第二個問題：

解析json數(shù)據(jù)。從上面的javascript中可以看到，我沒有使用jquery.parseJSON()這些方法，開始使用這些方法，但是總是會報

VM219:1 Uncaught SyntaxError: Unexpected token o in JSON at position 1的錯誤，后來不用jquery.parseJSON()這個方法，反而一切正常。不知為何。

以上這篇ajax調(diào)用返回php接口返回json數(shù)據(jù)的方法(必看篇)就是小編分享給大家的全部內(nèi)容了，希望能給大家一個參考，也希望大家多多支持腳本之家。

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