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C語言實(shí)現(xiàn)樹的動(dòng)態(tài)查找實(shí)例代碼

更新時(shí)間：2017年06月25日 11:44:56 投稿：lqh

這篇文章主要介紹了C語言實(shí)現(xiàn)樹的動(dòng)態(tài)查找實(shí)例代碼的相關(guān)資料,需要的朋友可以參考下

C語言實(shí)現(xiàn)樹的動(dòng)態(tài)查找實(shí)例代碼

本例演示一種樹數(shù)據(jù)結(jié)構(gòu)存儲(chǔ)記錄集合時(shí)的動(dòng)態(tài)查找方法。首先程序通過construct()函數(shù)，利用已經(jīng)存在的結(jié)構(gòu)體數(shù)組數(shù)據(jù)建立一個(gè)二叉樹，建立樹的過程中，要保證每個(gè)節(jié)點(diǎn)的值都大于它的左子樹上節(jié)點(diǎn)的值而小于它右子樹所有節(jié)點(diǎn)的值，該函數(shù)返回建立樹的根指針；然后通過函數(shù)Search(root,name)查找，如果找到相應(yīng)的數(shù)據(jù)，將其打印出來，如果沒有找到，則用戶可以選擇是否將該數(shù)據(jù)插入到樹中。

具體代碼如下：

#include <stdio.h>
#include <stdlib.h> 
#include <string.h>
#define NUM 4
 
struct tree
{
  char name[20];
  char city[20];
  char sex[10];
  char age[10];
  char job[10];
  struct tree *left;
  struct tree *right;
};
 
struct tree Datas[NUM]=
{
  "Willing","Tianjing","Female","21","worker",NULL,NULL,
  "Tom","Beijing","Male","31","doctor",NULL,NULL,
  "Sun","Weifang","Male","24","student",NULL,NULL,
  "Marry","Shanghai","Female","19","techer",NULL,NULL
};
 
struct tree *construct(
  struct tree *root, 
  struct tree *r, 
  struct tree *Data)
{
  if(!r)
  {
    r = (struct tree *)malloc(sizeof(struct tree));
    if(!r)
    {
      printf("內(nèi)存分配失??！");
      exit(0);
    }
    r->left = NULL;
    r->right = NULL;
    strcpy(r->name,Data->name);
    strcpy(r->city,Data->city);
    strcpy(r->sex,Data->sex);
    strcpy(r->age,Data->age);
    strcpy(r->job,Data->job);
    if(!root)
      return r;
    if(strcmp(Data->name,root->name)<0)
      root->left = r;
    else
      root->right = r;
    return r;
  }
  if(strcmp(Data->name,r->name)<0)
    construct(r,r->left,Data);
  else
    construct(r,r->right,Data);
 
  return root;  
}
 
struct tree *Search(root,name)
struct tree *root;
char name[];
{
  struct tree *p;
  if(root == NULL)
    printf("該樹為空\n");
  p = root;
  while(strcmp(p->name,name)!=0)
  {
    if(strcmp(p->name,name)>0)
      p = p->left;
    else
      p = p->right;
    if(p == NULL)
      break;
  }
  return(p);
}
 
void print(struct tree *r)
{
  if(!r)
    return;
  print(r->left);
  printf("%s\n",r->name);
  print(r->right);
}
 
void print_currentData(struct tree *point)
{
  if(point == NULL)
    return;
  printf("  姓名：%s\n",point->name);
  printf("  城市：%s\n",point->city);
  printf("  性別：%s\n",point->sex);
  printf("  年齡：%s\n",point->age);
  printf("  工作：%s\n",point->job);
}
 
int main(void)
{
  int i;
  char c[10];
  char swap[20];
  char name[20];
  struct tree *root,*p;
  struct tree *temp;
  p = NULL;
  temp = NULL;
  root = NULL;
  for(i = 0;i<NUM;i++)
    root =construct(root,root,&Datas[i]);
  printf("現(xiàn)有人員資料：\n");
  print(root);
  printf("請(qǐng)輸入要查找的人的名字\n");
  scanf("%s",name);
  p = Search(root,name);
  if(p == NULL)
  {
    printf("沒有該人資料\n");
    printf("是否要插入該人資料[y/n]\n");
    scanf("%s",c);
    if(strcmp(c,"y")==0)
    {
      temp = (struct tree *)malloc(sizeof(struct tree));
      if(!temp)
      {
        printf("內(nèi)存分配失?。?);
        exit(0);
      }
      printf("請(qǐng)輸入該人姓名：\n");
      scanf("%s",swap);
      strcpy(temp->name,swap);
      printf("請(qǐng)輸入該人所在城市：\n");
      scanf("%s",swap);
      strcpy(temp->city,swap);
      printf("請(qǐng)輸入該人性別[Male/Female]：\n");
      scanf("%s",swap);
      strcpy(temp->sex,swap);
      printf("請(qǐng)輸入該人年齡：\n");
      scanf("%s",swap);
      strcpy(temp->age,swap);
      printf("請(qǐng)輸入該人工作：\n");
      scanf("%s",swap);
      strcpy(temp->job,swap);
      temp->left = NULL;
      temp->right = NULL;
      root =construct(root,root,temp);
      print_currentData(temp);
      printf("現(xiàn)有人員資料：\n");
      root = root;
      print(root);
    }
    else
      return 0;
  }
  print_currentData(p);
  return 1;
}

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