快捷導(dǎo)航

C++實(shí)現(xiàn)拼圖游戲代碼（graphics圖形庫(kù)）

更新時(shí)間：2018年05月03日 14:14:06 作者：DB偉

這篇文章主要為大家詳細(xì)介紹了C++實(shí)現(xiàn)拼圖游戲代碼，帶有g(shù)raphics圖形庫(kù)，文中示例代碼介紹的非常詳細(xì)，具有一定的參考價(jià)值，感興趣的小伙伴們可以參考一下

本文實(shí)例為大家分享了C++實(shí)現(xiàn)拼圖游戲的具體代碼，供大家參考，具體內(nèi)容如下

#include<stdio.h> 
#include<stdlib.h> 
#include<conio.h> 
#include<windows.h> 
#include<graphics.h> 
#include<string.h> 
int map[4][3]; 
int num = 0; 
IMAGE image1, image2, image3, image4, image5, image6, image7, image8, image9, image10, image11, image12, image13; 
void Initmap()//初始化數(shù)組 
{ 
 for (int i = 0; i < 4; i++) 
 { 
 for (int j = 0; j < 3; j++) 
 { 
 map[i][j] = rand() % 100; 
 } 
 } 
 map[2][3] = 100; 
 
} 
void PaintInit()//獲取圖片地址內(nèi)容 
{ 
 loadimage(&image1, L"./image/1.jpg", 100, 100); 
 loadimage(&image2, L"./image/2.jpg", 100, 100); 
 loadimage(&image3, L"./image/3.jpg", 100, 100); 
 loadimage(&image4, L"./image/4.jpg", 100, 100); 
 loadimage(&image5, L"./image/5.jpg", 100, 100); 
 loadimage(&image6, L"./image/6.jpg", 100, 100); 
 loadimage(&image7, L"./image/7.jpg", 100, 100); 
 loadimage(&image8, L"./image/8.jpg", 100, 100); 
 loadimage(&image9, L"./image/9.jpg", 100, 100); 
 loadimage(&image10, L"./image/10.jpg", 100, 100); 
 loadimage(&image11, L"./image/11.jpg", 100, 100); 
 loadimage(&image12, L"./image/back.jpg", 400, 200); 
 loadimage(&image13, L"./image/border.jpg", 50, 300); 
 
} 
int finMin(int a)//找到數(shù)組里面最小的數(shù)，然后將設(shè)定的圖片給對(duì)應(yīng)的數(shù)； 
{ 
 int flag=1; 
 
 for (int i = 0; i < 4; i++) 
 { 
 for (int j = 0; j < 3; j++) 
 { 
 if (a > map[i][j]) 
 { 
 flag++;//如過(guò)flag 不加上去不變表示沒(méi)有比他大的數(shù) 
 } 
 } 
 } 
 return flag; 
} 
void GameInit()//游戲初始化 
{ 
 
 int min=map[0][0]; 
 putimage(450, 0, &image12); 
 putimage(400, 0, &image13); 
 for (int i = 0; i < 4; i++) 
 { 
 for (int j = 0; j < 3; j++) 
 { 
 if (finMin(map[i][j]) == 1) 
 { 
  putimage(i * 100, j * 100, &image1); 
 } 
 if (finMin(map[i][j]) == 2) 
 { 
  putimage(i * 100, j * 100, &image2); 
 } 
 if (finMin(map[i][j]) == 3) 
 { 
  putimage(i * 100, j * 100, &image3); 
 } 
 if (finMin(map[i][j]) == 4) 
 { 
  putimage(i * 100, j * 100, &image4); 
 } 
 if (finMin(map[i][j]) == 5) 
 { 
  putimage(i * 100, j * 100, &image5); 
 } 
 if (finMin(map[i][j]) == 6) 
 { 
  putimage(i * 100, j * 100, &image6); 
 } 
 if (finMin(map[i][j]) == 7) 
 { 
  putimage(i * 100, j * 100, &image7); 
 } 
 if (finMin(map[i][j]) == 8) 
 { 
  putimage(i * 100, j * 100, &image8); 
 } 
 if (finMin(map[i][j]) == 9) 
 { 
  putimage(i * 100, j * 100, &image9); 
 } 
 if (finMin(map[i][j]) == 10) 
 { 
  putimage(i * 100, j * 100, &image10); 
 } 
 if (finMin(map[i][j]) == 11) 
 { 
  putimage(i * 100, j * 100, &image11); 
 } 
  
 } 
 } 
 
} 
void PlayGame() 
{ 
 int x, y; 
 MOUSEMSG m; 
 int newA; 
 char ch; 
 int r, c; //找到當(dāng)前空白塊的下標(biāo) // 
 for (int i = 0; i < 4; i++) 
 { 
 for (int j = 0; j < 3; j++) 
 { 
 if (map[i][j] == 100) 
 { 
 r = i; 
 c = j; 
 } 
 } 
 } 
 
 
 ch = getch(); 
 switch (ch) 
 { 
 
 case 'W':case 'w' : 
 { 
 
 if (c - 1<0)return; 
 newA = map[r][c]; 
 map[r][c] = map[r][c-1]; 
 map[r][c-1] = newA; 
 num++; 
 break; 
 } 
 case 'S':case 's': 
 { 
 if (c + 1>2)return; 
 newA = map[r][c]; 
 map[r][c] = map[r][c+1]; 
 map[r][c+1] = newA; 
 num++; 
 break; 
 } 
 case 'A':case 'a': 
 { 
 if (r - 1<0)return; 
 newA = map[r][c]; 
 map[r][c] = map[r-1][c]; 
 map[r-1][c] = newA; 
 num++; 
 break; 
 } 
 case 'd':case 'D': 
 { 
 if(r+1>3)return; 
 newA = map[r][c]; 
 map[r][c] = map[r+1][c]; 
 map[r+1][c] = newA; 
 num++; 
 break; 
 } 
 } 
} 
int main()//最后如果圖像游戲如果拼完整后，數(shù)組的數(shù)會(huì)是從小到大的，以此來(lái)判別是否拼圖完整 
{ 
 TCHAR sql[200]; 
 initgraph(850, 300); 
 Initmap(); 
 PaintInit(); 
 
 while (1) 
 { 
 cleardevice(); 
 BeginBatchDraw(); 
 GameInit(); 
 outtextxy(650, 210, _T("原圖")); 
 _stprintf(sql, _T("走了:%d"), num); 
 outtextxy(500, 250, sql); 
 EndBatchDraw(); 
 PlayGame(); 
 } 
 getch(); 
 closegraph(); 
 system("pause"); 
 return 
}

效果圖：