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jsp Hibernate入門教程第2/3頁

 更新時(shí)間:2008年11月14日 23:08:55   作者:  
如果您是在同一個(gè)Session中取出數(shù)據(jù)并想要馬上進(jìn)行更新,則只要先查詢并取出對(duì)象,透過setXXX()方法設(shè)定好新的值,然后呼叫session.flush()即可在同一個(gè)Session中更新指定的數(shù)據(jù)

 如果您開啟了一個(gè)Session,從數(shù)據(jù)表中取出數(shù)據(jù)顯示到使用者接口上,之后關(guān)閉Session,當(dāng)使用者在接口上操作完畢并按下儲(chǔ)存時(shí),這時(shí)您要重新開啟一個(gè)Session,使用update()方法將對(duì)象中的數(shù)據(jù)更新至對(duì)應(yīng)的數(shù)據(jù)表中,一個(gè)例子如下: 
復(fù)制代碼 代碼如下:

HibernateTest.java
import onlyfun.caterpillar.*;
import net.sf.hibernate.*;
import net.sf.hibernate.cfg.*;
import java.util.*;
public class HibernateTest {
public static void main(String[] args) throws HibernateException {
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();
List users = session.find("from User");
// 關(guān)閉這個(gè)Session
session.close();
User updated = null;
for (ListIterator iterator = users.listIterator(); iterator.hasNext(); ) {
User user = (User) iterator.next();
if(updated == null)
updated = user;
System.out.println(user.getName() +
"\n\tAge: " + user.getAge() +
"\n\tSex: " + user.getSex());
}
// 使用者作一些操作,之后儲(chǔ)存
updated.setName("caterpillar");
// 開啟一個(gè)新的Session
session = sessionFactory.openSession();
// 更新數(shù)據(jù)
session.update(updated);
users = session.find("from User");
session.close();
sessionFactory.close();
for (ListIterator iterator = users.listIterator(); iterator.hasNext(); ) {
User user = (User) iterator.next();
System.out.println(user.getName() +
"\n\tAge: " + user.getAge() +
"\n\tSex: " + user.getSex());
}
}
}

 這個(gè)程序執(zhí)行的結(jié)果范例如下,您可以看看實(shí)際上執(zhí)行了哪些SQL:
log4j:WARN No appenders could be found for logger (net.sf.hibernate.cfg.Environment).
log4j:WARN Please initialize the log4j system properly.
Hibernate: select user0_.user_id as user_id, user0_.name as name, user0_.sex as sex, user0_.age as age from USER user0_
justin
Age: 28
Sex: M
momor
Age: 25
Sex: F
Bush
Age: 25
Sex: M
Becky
Age: 35
Sex: F
Hibernate: update USER set name=?, sex=?, age=? where user_id=?
Hibernate: select user0_.user_id as user_id, user0_.name as name, user0_.sex as sex, user0_.age as age from USER user0_
caterpillar
Age: 28
Sex: M
momor
Age: 25
Sex: F
Bush
Age: 25
Sex: M
Becky
Age: 35
Sex: F

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