C語言實現(xiàn)停車場管理系統(tǒng)
問題描述:停車場是一個能放n輛車的狹長通道,只有一個大門,汽車按到達的先后次序停放。若車場滿了,車要停在門外的便道上等候,一旦有車走,則便道上第一輛車進入。當停車場中的車離開時,由于通道窄,在它后面呢的車要先退出,待它走后再依次進入。汽車離開時按停放時間收費。
基本功能要求:
(1)建立三個數(shù)據(jù)結構分別是:停放隊列、讓路棧、等候隊列。
(2)輸入數(shù)據(jù)模擬管理過程,數(shù)據(jù)(入或出,車號)。
停車管理系統(tǒng)是C語言中隊列和棧比較簡單的應用,需要注意的是停車隊列、等候隊列、讓路棧結構體的構建。在寫代碼時,出隊列入棧和出棧入隊列時,指針容易出錯而造成段錯誤,應當注意。我所寫的代碼如下:
//定義結構體
#include <stdio.h>
#include <stdlib.h>
#define F 0
#define T 1
#define MAX 3
typedef struct Node //數(shù)據(jù)
{
int number;
int time;
}Node;
typedef struct QueueNode //隊列結點
{
struct Node infom;
struct QueueNode * next;
}*QueueNode;
typedef struct LinkQueue //鏈隊列
{
struct QueueNode * front;
struct QueueNode * rear;
}LinkQueue;
typedef struct stack //棧結點
{
struct Node data;
struct stack *next;
}*StackNode;
typedef struct LinkStack //鏈棧
{
StackNode top;
int count;
}LinkStack;
//函數(shù)實現(xiàn)
void menu(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t);//菜單
int init(LinkQueue *wait,LinkQueue *park,LinkStack *giveway);//初始化
int linklength(LinkQueue q);//查看長度
int enqueue(LinkQueue *q,int num,int t);//入隊列
int dequeue(LinkQueue *q,int *num,int *t);//出隊列
void park1(LinkQueue *wait,LinkQueue *park);//停車函數(shù)
int push(LinkStack *s,int num,int t);//入棧
int pop(LinkStack *s,int *num,int *t);//出棧
void leave2(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t);//離開函數(shù)
void view3(LinkQueue wait,LinkQueue park);//查看停車場狀態(tài)
int main()
{
LinkQueue wait;
LinkQueue park;
LinkStack giveway;
int num = 0;
int t = 0;
init(&wait,&park,&giveway);
menu(&wait,&park,&giveway,num,t);
return 0;
}
int init(LinkQueue *wait,LinkQueue *park,LinkStack *giveway)
{
QueueNode newnode1 = (QueueNode)malloc(sizeof(struct QueueNode));
if(NULL == newnode1)
{
return F;
}
newnode1->next = NULL;
wait->front = newnode1;
wait->rear = newnode1;
QueueNode newnode2 = (QueueNode)malloc(sizeof(struct QueueNode));
if(NULL == newnode2)
{
return F;
}
newnode2->next = NULL;
park->front = newnode2;
park->rear = newnode2;
giveway->top = NULL;
giveway->count = 0;
}
void menu(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t)
{
printf("**********Welcome to our Car Parking !**********\n");
printf("********** Please choose function **********\n");
printf("********** 1 : park. **********\n");
printf("********** 2 : leave. **********\n");
printf("********** 3 : view. **********\n");
printf("********** 4 : exit. **********\n");
int option;
scanf("%d",&option);
switch(option)
{
case 1:{
park1(wait,park);
printf("停車完成!\n");
menu(wait,park,giveway,num,t);
break;
}
case 2:{
leave2(wait,park,giveway,num,t);
menu(wait,park,giveway,num,t);
break;
}
case 3:{
view3(*wait,*park);
menu(wait,park,giveway,num,t);
break;
}
case 4:{
printf("********** 歡迎再次使用,謝謝! **********\n");
break;
}
default:{
printf("********** 請輸入正確的指令! **********\n");
menu(wait,park,giveway,num,t);
break;
}
}
}
int linklength(LinkQueue q)
{
int i = 0;
while(q.front != q.rear)
{
i++;
q.front = q.front->next;
}
return i;
}
int enqueue(LinkQueue *q,int num,int t)
{
QueueNode newnode = (QueueNode)malloc(sizeof(struct QueueNode));
if(NULL == newnode)
{
return F;
}
newnode->infom.number = num;
newnode->infom.time = t;
newnode->next = NULL;
q->rear->next = newnode;
q->rear = newnode;
return T;
}
int dequeue(LinkQueue *q,int *num,int *t)
{
if(q->front == q->rear)
{
printf("the queue is empty!\n");
return F;
}
*num = q->front->next->infom.number;
*t = q->front->next->infom.time;
QueueNode temp = q->front->next;
q->front->next = temp->next;
if(temp->next == NULL)
{
q->rear = q->front;
}
free(temp);
return T;
}
void park1(LinkQueue *wait,LinkQueue *park)
{
printf("請輸入車號和停車時間\n");
int num,t;
scanf("%d,%d",&num,&t);
if(linklength(*park) >= MAX)
{
printf("停車場已滿,進入等待區(qū)!\n");
enqueue(wait,num,t);
}
else
{
enqueue(park,num,t);
}
}
int push(LinkStack *s,int num,int t)
{
StackNode newnode = (StackNode)malloc(sizeof(struct stack));
if(NULL == newnode)
{
return F;
}
newnode->data.number = num;
newnode->data.time = t;
newnode->next = s->top;
s->top = newnode;
s->count++;
return T;
}
int pop(LinkStack *s,int *num,int *t)
{
if(0 == s->count)
{
printf("the stack is empty !\n");
return F;
}
*num = s->top->data.number;
*t = s->top->data.time;
StackNode temp = s->top;
s->top = s->top->next;
free(temp);
s->count--;
return T;
}
void leave2(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t)
{
printf("請輸入要離開車的車號\n");
int leavenumber;
scanf("%d",&leavenumber);
int i = 0;
QueueNode head = park->front;
while(head != park->rear)
{
if(head->next->infom.number != leavenumber)
{
head = head->next;
i++;
}
else
break;
}
int j = 0;
if(i <= MAX-1)
{
while(j != i)
{
dequeue(park,&num,&t);
push(giveway,num,t);
j++;
}
dequeue(park,&num,&t);
}
else
{
printf("查無此車!\n");
}
while(giveway->top != NULL)
{
pop(giveway,&num,&t);
enqueue(park,num,t);
}
if(linklength(*wait) != 0)
{
dequeue(wait,&num,&t);
enqueue(park,num,t);
}
}
void view3(LinkQueue wait,LinkQueue park)
{
printf("******************** 目前停車場狀況 ********************\n");
printf("停車場共%d個車位,當前停車場共有%d量車,等待區(qū)共有%d量車\n",
MAX,linklength(park),linklength(wait));
printf("**************************************************************\n");
printf("車 號:");
QueueNode head1 = park.front;
QueueNode head2 = park.front;
while(head1 != park.rear)
{
printf("%d ",head1->next->infom.number);
head1 = head1->next;
}
printf("\n");
printf("停車時間:");
while(head2 != park.rear)
{
printf("%d ",head2->next->infom.time);
head2 = head2->next;
}
printf("\n");
}
更多學習資料請關注專題《管理系統(tǒng)開發(fā)》。
以上就是本文的全部內(nèi)容,希望對大家的學習有所幫助,也希望大家多多支持腳本之家。
相關文章
C語言fgetc和fputc函數(shù)用法詳解(以字符形式讀寫文件)
這篇文章主要介紹了C語言fgetc和fputc函數(shù)用法詳解(以字符形式讀寫文件),文中通過示例代碼介紹的非常詳細,對大家的學習或者工作具有一定的參考學習價值,需要的朋友們下面隨著小編來一起學習學習吧2021-01-01

