//stack.h
#ifndef STACK_H
#define STACK_H
#include<iostream>
class stack_int
{
private:
 int* bottom;   //棧底
 int* top;    //棧頂
 unsigned int capacity;//棧容量
 unsigned int size; //棧大小
public:
 stack_int() :bottom(new int[11]), top(bottom), capacity(10), size(0) {};
 stack_int(unsigned int capacity) :bottom(new int[capacity+1]),top(bottom), capacity(capacity),size(0){};
 int operator[](unsigned int i) const
 {
 return *(bottom + i);
 }
 bool isEmpty()const { return bottom == top; }
 bool isFull()const { return size == capacity-1; }
 unsigned int getsize()const { return size; }
 unsigned int getcapacity()const { return capacity; }
 int gettop()const
 {
 if (!isEmpty())
 return *(top - 1);
 else
 return -1;
 }
 void settop(int i)
 {
 if (!isEmpty())
 {
 *(top - 1) = i;
 }
 }
 void push(int i)
 {
 if ((top - bottom)<capacity)
 {
 *top = i;
 top++;
 size++;
 }
 else
 {
 std::cout << "stack full!" << std::endl;
 stack_expansion();
 push(i);
 }
 }
 int pop(int &val)
 {//返回值為1則棧未空，返回值為0則棧已空無(wú)法出棧
 if (top > bottom)
 {
 top--;
 size--;
 val = *top;
 return 1;
 }
 else
 {
 std::cout << "stack empty!" << std::endl;
 return NULL;
 }
 }
private:
 void stack_expansion()
 {//棧擴(kuò)容
 std::cout << "正在擴(kuò)容中..." << std::endl;
 int newcapacity = 2 * capacity + 1;
 int* newbottom = new int[newcapacity + 1];
 int* newtop = newbottom;
 for (int i = 0; i < size; ++i)
 {
 *newtop = *bottom;
 newtop++;
 bottom++;
 }
 bottom = newbottom;
 top = newtop;
 capacity = newcapacity;
 }
};

#endif

//Main.c
#include"stack.h"
#include<iostream>
using namespace std;
bool is_digit(char i)
{//是數(shù)字
 if (i == '1' || i == '2' || i == '3' || i == '4' || i == '5' || i == '6' || i == '7' || i == '8' || i == '9' || i == '0')
 return true;
 else return false;
}
bool is_operator(char i)
{//是運(yùn)算符
 if (i == '+' || i == '-' || i == '*' || i == '/' || i == '(' || i == ')'||i=='=')
 return true;
 else return false;
}
bool get_priority(char pre,char cur)
{//獲取兩個(gè)符號(hào)間的優(yōu)先級(jí),pre為靠前的字符，cur為靠后的字符
 if ((pre == '+' || pre == '-') && (cur == '*' || cur == '/'))
 return false;
 else if (pre == '(' || cur == '(')
 return false;
 else
 return true;
}
int do_operation(int lnum, char ope, int rnum)
{
 if (ope == '+')
 return lnum + rnum;
 if (ope == '-')
 return lnum - rnum;
 if (ope == '*')
 return lnum * rnum;
 if (ope == '/')
 return lnum / rnum;
}
/*
1+2*3=
1*(2+1*(3+5)+4*3)=
先乘除，后加減，有括號(hào)先算括號(hào)內(nèi)的
1+5*4-345+36/6*4+145*4*5-52=
*/

void do_arithmetic()
{
 stack_int s;
 stack_int num_stack;//數(shù)據(jù)棧
 stack_int ope_stack;//符號(hào)棧
 char current_char;
 current_char = getchar();
 bool overflag = false;//結(jié)束標(biāo)志
 bool errorflag = false;//出錯(cuò)標(biāo)志
 while (overflag != true)
 {//未遇到=號(hào)時(shí)不斷進(jìn)行四則運(yùn)算
 if (is_digit(current_char))
 {//遇到數(shù)字符號(hào)則將完整的數(shù)解析出來(lái)并保存于棧中
 int num = 0;
 num = current_char - '0';//符號(hào)轉(zhuǎn)數(shù)字
 current_char = getchar();//獲取下一個(gè)字符
 while (is_digit(current_char))
 {
 num = num * 10 + (current_char - '0');
 current_char = getchar();
 }
 num_stack.push(num);
 //cout <<"the number is " <<num << endl;
 }
 if (current_char == ' '||current_char=='\n')
 {//空格或換行則繼續(xù)
 current_char = getchar();
 continue;
 }
 if (is_operator(current_char))
 {//遇到運(yùn)算符則將運(yùn)算符保存于運(yùn)算符棧中
 int ope = '?';
 //如果當(dāng)前符號(hào)棧非空，則不斷根據(jù)優(yōu)先級(jí)決定是否進(jìn)行一次運(yùn)算
 while ((!ope_stack.isEmpty()) && (get_priority((char)ope_stack.gettop(), current_char)))
 {//如果前一個(gè)運(yùn)算符優(yōu)先級(jí)更高
 ope_stack.pop(ope);
 //cout << "找到了前一個(gè)運(yùn)算符為: " << (char)ope << endl;
 int lnum, rnum;
 //符號(hào)棧非空時(shí)，數(shù)據(jù)棧應(yīng)該至少有兩個(gè)數(shù)，否則出錯(cuò)
 if (num_stack.isEmpty())
 {
  cout << "error: 數(shù)據(jù)棧缺失兩個(gè)元素，解析失?。? << endl;
  errorflag = true;
  overflag = true;
  break;
 }
 num_stack.pop(rnum);
 if (num_stack.isEmpty())
 {
  cout << "error: 數(shù)據(jù)棧缺失一個(gè)元素，解析失??！" << endl;
  errorflag = true;
  overflag = true;
  break;
 }
 num_stack.pop(lnum);
 lnum = do_operation(lnum, (char)ope, rnum);//進(jìn)行運(yùn)算
 num_stack.push(lnum);
 }
 if (current_char == '=')
 {//如果解析到=號(hào)了,解析完成
 if (!ope_stack.isEmpty())
 {
  errorflag = true;
  cout << "error: 缺失)" << endl;
 }
 overflag = true;
 break;
 }
 ope_stack.push(current_char);
 if (current_char == ')')
 {//右括號(hào)則出棧兩次，將右括號(hào)和匹配的左括號(hào)出棧
 ope_stack.pop(ope);
 if (ope_stack.isEmpty())
 {
  cout << "error: 沒(méi)有與)相匹配的(" << endl;
  errorflag = true;
  overflag = true;
  break;
 }
 ope_stack.pop(ope);
 }
 current_char = getchar();
 }
 }
 //for (int i = 0; i < num_stack.getsize(); ++i)
 // cout << num_stack[i] << "\t";
 //cout << endl;
 //for (int i = 0; i < ope_stack.getsize(); ++i)
 // cout << (char)ope_stack[i] << "\t";
 if (!errorflag)
 cout << num_stack.gettop() << endl;
}

int main()
{
 cout << " ______________" << endl;
 cout << "|整數(shù)四則運(yùn)算器|" << endl;
 cout << " --------------" << endl;
 cout << "功能介紹：進(jìn)行整數(shù)表達(dá)式的四則運(yùn)算" << endl;
 cout << "可以使用的運(yùn)算符:+ - * /" << endl;
 cout << "使用方式:輸入以=結(jié)尾的算數(shù)運(yùn)算表達(dá)式,回車后即可得到運(yùn)算結(jié)果" << endl;
 cout << endl;
 //2432+5423-534*42=
 while (true)
 {
 cout << "____________________" << endl;
 cout << "--------------------" << endl;
 cout << "> ";
 do_arithmetic();
 }
 return 0;
}