詳解JavaScript中分解數(shù)字的三種方法
本文基于免費代碼營基本算法腳本“分解數(shù)字”
在數(shù)學(xué)中,非負(fù)整數(shù)n的階乘可能是一個棘手的算法。在本文中,我將解釋這種方法,首先使用遞歸函數(shù),第二種使用而循環(huán),第三種使用以循環(huán)。
算法挑戰(zhàn)
返回提供的整體的階乘。
如果整體用字母n表示,則階乘是所有小于或等于n的正整數(shù)的乘積。
階乘經(jīng)常用簡寫符號n!表示!
例如:5!= 1 * 2 * 3 * 4 * 5 = 120
function factorialize(num) {
return num;
}
factorialize(5);
提供的測試用例
- factorialize(0)應(yīng)該返回1
- factorialize(5)應(yīng)該返回120
- factorialize(10)應(yīng)該返回3628800
- factorialize(20)應(yīng)該返回2432902008176640000
什么是因數(shù)分解?
當(dāng)將一個因數(shù)分解時,就是稱為數(shù)字乘以每個連續(xù)的數(shù)字減一個。
如果您的電話號碼是5,則您將:
5! = 5 * 4 * 3 * 2 * 1
該模式為:
0! = 1
1! = 1
2! = 2 * 1
3! = 3 * 2 * 1
4! = 4 * 3 * 2 * 1
5! = 5 * 4 * 3 * 2 * 1
1.遞歸分解一個數(shù)字
function factorialize(num) {
// If the number is less than 0, reject it.
if (num < 0)
return -1;
// If the number is 0, its factorial is 1.
else if (num == 0)
return 1;
// Otherwise, call the recursive procedure again
else {
return (num * factorialize(num - 1));
/*
First Part of the recursion method
You need to remember that you won't have just one call, you'll have several nested calls
Each call: num === "?" num * factorialize(num - 1)
1st call – factorialize(5) will return 5 * factorialize(5 - 1) // factorialize(4)
2nd call – factorialize(4) will return 4 * factorialize(4 - 1) // factorialize(3)
3rd call – factorialize(3) will return 3 * factorialize(3 - 1) // factorialize(2)
4th call – factorialize(2) will return 2 * factorialize(2 - 1) // factorialize(1)
5th call – factorialize(1) will return 1 * factorialize(1 - 1) // factorialize(0)
Second part of the recursion method
The method hits the if condition, it returns 1 which num will multiply itself with
The function will exit with the total value
5th call will return (5 * (5 - 1)) // num = 5 * 4
4th call will return (20 * (4 - 1)) // num = 20 * 3
3rd call will return (60 * (3 - 1)) // num = 60 * 2
2nd call will return (120 * (2 - 1)) // num = 120 * 1
1st call will return (120) // num = 120
If we sum up all the calls in one line, we have
(5 * (5 - 1) * (4 - 1) * (3 - 1) * (2 - 1)) = 5 * 4 * 3 * 2 * 1 = 120
*/
}
}
factorialize(5);
沒有注釋:
function factorialize(num) {
if (num < 0)
return -1;
else if (num == 0)
return 1;
else {
return (num * factorialize(num - 1));
}
}
factorialize(5);
2.用WHILE循環(huán)分解一個數(shù)字
function factorialize(num) {
// Step 1. Create a variable result to store num
var result = num;
// If num = 0 OR num = 1, the factorial will return 1
if (num === 0 || num === 1)
return 1;
// Step 2. Create the WHILE loop
while (num > 1) {
num--; // decrementation by 1 at each iteration
result = result * num; // or result *= num;
/*
num num-- var result result *= num
1st iteration: 5 4 5 20 = 5 * 4
2nd iteration: 4 3 20 60 = 20 * 3
3rd iteration: 3 2 60 120 = 60 * 2
4th iteration: 2 1 120 120 = 120 * 1
5th iteration: 1 0 120
End of the WHILE loop
*/
}
// Step 3. Return the factorial of the provided integer
return result; // 120
}
factorialize(5);
沒有注釋:
function factorialize(num) {
var result = num;
if (num === 0 || num === 1)
return 1;
while (num > 1) {
num--;
result *= num;
}
return result;
}
factorialize(5);
3.使用FOR循環(huán)分解數(shù)字
function factorialize(num) {
// If num = 0 OR num = 1, the factorial will return 1
if (num === 0 || num === 1)
return 1;
// We start the FOR loop with i = 4
// We decrement i after each iteration
for (var i = num - 1; i >= 1; i--) {
// We store the value of num at each iteration
num = num * i; // or num *= i;
/*
num var i = num - 1 num *= i i-- i >= 1?
1st iteration: 5 4 = 5 - 1 20 = 5 * 4 3 yes
2nd iteration: 20 3 = 4 - 1 60 = 20 * 3 2 yes
3rd iteration: 60 2 = 3 - 1 120 = 60 * 2 1 yes
4th iteration: 120 1 = 2 - 1 120 = 120 * 1 0 no
5th iteration: 120 0 120
End of the FOR loop
*/
}
return num; //120
}
factorialize(5);
沒有注釋:
function factorialize(num) {
if (num === 0 || num === 1)
return 1;
for (var i = num - 1; i >= 1; i--) {
num *= i;
}
return num;
}
factorialize(5);
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