Java基礎之二叉搜索樹的基本操作
更新時間:2021年05月23日 09:36:27 作者:保護眼睛
發(fā)現許多小伙伴還不清楚Java二叉搜索樹的基本操作,今天特地整理了這篇文章,文中有非常詳細的代碼示例,對正在學習Java的小伙伴很有幫助,需要的朋友可以參考下
一、二叉搜索樹插入元素
/** * user:ypc; * date:2021-05-18; * time: 15:09; */ class Node { int val; Node left; Node right; Node(int val) { this.val = val; } } public void insert(int key) { Node node = new Node(key); if (this.root == null) { root = node; } Node cur = root; Node parent = null; while (cur != null) { if (cur.val == key) { //System.out.println("元素已經存在"); return; } else if (cur.val > key) { parent = cur; cur = cur.left; } else { parent = cur; cur = cur.right; } } if (key > parent.val) { parent.right = node; } else { parent.left = node; } }
二、搜索指定節(jié)點
public boolean search(int key) { Node cur = root; while (cur != null) { if (cur.val == key) { return true; } else if (cur.val > key) { cur = cur.left; } else { cur = cur.right; } } return false; }
三、刪除節(jié)點方式一
public void removenode1(Node parent, Node cur) { if (cur.left == null) { if (cur == root) { root = cur.right; } else if (cur == parent.right) { parent.left = cur.right; } else { parent.right = cur.right; } } else if (cur.right == null) { if (cur == root) { root.left = cur; } else if (cur == parent.right) { parent.right = cur.left; } else { parent.left = cur.left; } } else { Node tp = cur; Node t = cur.right; while (t.left != null) { tp = t; t = t.left; } if (tp.left == t) { cur.val = t.val; tp.left = t.right; } if (tp.right == t) { cur.val = t.val; tp.right = t.right; } } } public void remove(int key) { Node cur = root; Node parent = null; while (cur != null) { if (cur.val == key) { removenode1(parent, cur); //removenode2(parent, cur); return; } else if (key > cur.val) { parent = cur; cur = cur.right; } else { parent = cur; cur = cur.left; } } }
四、刪除節(jié)點方式二
public void removenode2(Node parent, Node cur) { if (cur.left == null) { if (cur == root) { root = cur.right; } else if (cur == parent.right) { parent.left = cur.right; } else { parent.right = cur.right; } } else if (cur.right == null) { if (cur == root) { root.left = cur; } else if (cur == parent.right) { parent.right = cur.left; } else { parent.left = cur.left; } } else { Node tp = cur; Node t = cur.left; while (t.right != null) { tp = t; t = t.right; } if (tp.right == t) { cur.val = t.val; tp.right = t.left; } if (tp.left == t) { cur.val = t.val; tp.left = t.left; } } }
五、運行結果
/** * user:ypc; * date:2021-05-18; * time: 15:09; */ class TestBinarySearchTree { public static void main(String[] args) { int a[] = {5, 3, 4, 1, 7, 8, 2, 6, 0, 9}; BinarySearchTree binarySearchTree = new BinarySearchTree(); for (int i = 0; i < a.length; i++) { binarySearchTree.insert(a[i]); } binarySearchTree.inOrderTree(binarySearchTree.root); System.out.println(); binarySearchTree.preOrderTree(binarySearchTree.root); binarySearchTree.remove(7); System.out.println(); System.out.println("方法一刪除后"); binarySearchTree.inOrderTree(binarySearchTree.root); System.out.println(); binarySearchTree.preOrderTree(binarySearchTree.root); } }
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