C語言分裝實現(xiàn)三子棋游戲詳解

更新時間：2021年05月28日 13:37:44 作者：m0_55394957

這篇文章主要為大家詳細介紹了C語言分裝實現(xiàn)三子棋游戲，文中示例代碼介紹的非常詳細，具有一定的參考價值，感興趣的小伙伴們可以參考一下

本文實例為大家分享了C語言分裝實現(xiàn)三子棋游戲的具體代碼，供大家參考，具體內(nèi)容如下

test.c --------------測試游戲的邏輯
game.h------------關于游戲相關函數(shù)的聲明
game.c------------游戲相關函數(shù)的實現(xiàn)

game.h

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
//符號的定義
#define ROW 3
#define COL 3
//函數(shù)聲明
void InitBoard(char board[ROW][COL], int row, int col);         //初始化棋盤

void DisplayBoard(char board[ROW][COL], int row, int col);      //打印棋盤

void PlayMove(char board[ROW][COL], int row, int col);          //玩家下

char IsWin(char board[ROW][COL], int row, int col);             //判斷輸贏

void ComputerMove(char board[ROW][COL], int row, int col);      //電腦下

game.c

#include"game.h"
void InitBoard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   board[i][j] =' ';
  }
 }
}
void DisplayBoard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   printf(" %c ", board[i][j]);
   if (j < col - 1)
    printf("|");
  }
  printf("\n");
  if (i < row - 1)
  {
   for (j = 0; j < col; j++)
   {
    printf("---");
    if (j < col - 1)
     printf("|");
   }
   printf("\n");
  }
 }
}
void PlayMove(char board[ROW][COL], int row, int col)
{
 int x = 0;
 int y = 0;
 printf("玩家走，請輸入坐標;>\n");
 scanf("%d %d", &x, &y);
 while (1)
 {
  if (x >= 1 && x <= row && y >= 1 && y <= col)  //判斷坐標是否合法
  {
   if (board[x-1][y-1] == ' ')   //判斷坐標是否被占用
   {
    board[x-1][y-1] = '*';
    break;
   }
   else
    printf("坐標已被占用，請重新輸入\n");
  }
  else
   printf("坐標非法，請重新輸入\n");
 }
}
void ComputerMove(char board[ROW][COL], int row, int col)
{
 printf("電腦走\n");
 while (1)
 {
  int x = rand() % row;
  int y = rand() % col;
  if (board[x][y] == ' ')    //判斷坐標是否被占用
  {
   board[x][y] = '#';
   break;
  }
 }
}
int IsFull(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   if(board[i][j] == ' ')
   return 0;    //棋盤未滿
  }
 }
 return 1;    // 棋盤滿了
}
char IsWin(char board[ROW][COL], int row, int col)
{
 /*玩家贏     返回*
 電腦贏     返回#
 平局       返回P
 繼續(xù)游戲   返回Q*/
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] != ' ')
   //判斷行是否相等
   return board[i][0];
 }
 for (i = 0; i < col; i++)
 {
  if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[1][i] != ' ')
   //判斷列是否相等
   return board[1][i];
 }
 if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ')
  //判斷對角線是否相等
  return board[1][1];
 if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != ' ')
  //判斷對角線是否相等
  return board[0][2];
 int ret=IsFull(board, row, col);   // 判斷是否平局（即判斷棋盤是否已滿）  此處row，col均為小寫
 //如果棋盤滿了返回1，未滿返回0
 if (ret == 1)
  return 'P';
 return 'Q';    //游戲繼續(xù)
}

test.c

#include"game.h"
void menu()
{
 printf("********************\n");
 printf("*****1.Play ********\n");
 printf("*****0.Exit ********\n");
}
void game()
{
 char board[ROW][COL];
 char ret=0;     //接收游戲狀態(tài)
 InitBoard(board, ROW, COL);  //初始化棋盤
 DisplayBoard(board, ROW, COL); //打印棋盤
 while (1)
 {
  PlayMove(board, ROW, COL);    //玩家走
  DisplayBoard(board, ROW, COL);
  ret=IsWin(board, ROW, COL);   //判斷輸贏
  if (ret != 'Q')
   break;
  ComputerMove(board, ROW, COL);    //電腦走
  DisplayBoard(board, ROW, COL);
  ret = IsWin(board, ROW, COL);     //判斷輸贏
  if (ret != 'Q')
   break;
 }
 if (ret == '*')
  printf("玩家勝\n");
 if(ret=='#')
  printf("電腦勝\n");
 if (ret == 'P')
  printf("平局\n");
 DisplayBoard(board, ROW, COL);   //展示棋盤
}
int main()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 do
 {
  menu();
  printf("請選擇;>\n");
  scanf("%d", &input);
  switch (input)
  {
  case 1:
   {
    printf("開始游戲\n");
    game();
    break;
   }
  case 0:
   {
    printf("退出游戲\n");
    break;
   }
  default:
   {
    printf("選擇錯誤，請重新選擇;>\n");
   }
  }
 } while (input);
 return 0;
}

代碼實現(xiàn)結果圖