C++實現(xiàn)LeetCode(8.字符串轉(zhuǎn)為整數(shù))
[LeetCode] 8. String to Integer (atoi) 字符串轉(zhuǎn)為整數(shù)
Implement atoi which converts a string to an integer.
The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.
The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.
If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.
If no valid conversion could be performed, a zero value is returned.
Note:
- Only the space character
' '
is considered as whitespace character. - Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. If the numerical value is out of the range of representable values, INT_MAX (231 − 1) or INT_MIN (−231) is returned.
Example 1:
Input: "42"
Output: 42
Example 2:
Input: " -42"
Output: -42
Explanation: The first non-whitespace character is '-', which is the minus sign.
Then take as many numerical digits as possible, which gets 42.
Example 3:
Input: "4193 with words"
Output: 4193
Explanation: Conversion stops at digit '3' as the next character is not a numerical digit.
Example 4:
Input: "words and 987"
Output: 0
Explanation: The first non-whitespace character is 'w', which is not a numerical
digit or a +/- sign. Therefore no valid conversion could be performed.
Example 5:
Input: "-91283472332"
Output: -2147483648
Explanation: The number "-91283472332" is out of the range of a 32-bit signed integer.
Thefore INT_MIN (−231) is returned.
字符串轉(zhuǎn)為整數(shù)是很常用的一個函數(shù),由于輸入的是字符串,所以需要考慮的情況有很多種。博主之前有一篇文章是關于驗證一個字符串是否為數(shù)字的,參見 Valid Number。在那篇文章中,詳細的討論了各種情況,包括符號,自然數(shù),小數(shù)點的出現(xiàn)位置,判斷他們是否是數(shù)字。個人以為這道題也應該有這么多種情況。但是這題只需要考慮數(shù)字和符號的情況:
1. 若字符串開頭是空格,則跳過所有空格,到第一個非空格字符,如果沒有,則返回0.
2. 若第一個非空格字符是符號 +/-,則標記 sign 的真假,這道題還有個局限性,那就是在 c++ 里面,+-1 和-+1 都是認可的,都是 -1,而在此題里,則會返回0.
3. 若下一個字符不是數(shù)字,則返回0,完全不考慮小數(shù)點和自然數(shù)的情況,不過這樣也好,起碼省事了不少。
4. 如果下一個字符是數(shù)字,則轉(zhuǎn)為整形存下來,若接下來再有非數(shù)字出現(xiàn),則返回目前的結果。
5. 還需要考慮邊界問題,如果超過了整型數(shù)的范圍,則用邊界值替代當前值。
C++ 解法:
class Solution { public: int myAtoi(string str) { if (str.empty()) return 0; int sign = 1, base = 0, i = 0, n = str.size(); while (i < n && str[i] == ' ') ++i; if (i < n && (str[i] == '+' || str[i] == '-')) { sign = (str[i++] == '+') ? 1 : -1; } while (i < n && str[i] >= '0' && str[i] <= '9') { if (base > INT_MAX / 10 || (base == INT_MAX / 10 && str[i] - '0' > 7)) { return (sign == 1) ? INT_MAX : INT_MIN; } base = 10 * base + (str[i++] - '0'); } return base * sign; } };
Java 解法:
public class Solution { public int myAtoi(String str) { if (str.isEmpty()) return 0; int sign = 1, base = 0, i = 0, n = str.length(); while (i < n && str.charAt(i) == ' ') ++i; if (i < n && (str.charAt(i) == '+' || str.charAt(i) == '-')) { sign = (str.charAt(i++) == '+') ? 1 : -1; } while (i < n && str.charAt(i) >= '0' && str.charAt(i) <= '9') { if (base > Integer.MAX_VALUE / 10 || (base == Integer.MAX_VALUE / 10 && str.charAt(i) - '0' > 7)) { return (sign == 1) ? Integer.MAX_VALUE : Integer.MIN_VALUE; } base = 10 * base + (str.charAt(i++) - '0'); } return base * sign; } }
到此這篇關于C++實現(xiàn)LeetCode(8.字符串轉(zhuǎn)為整數(shù))的文章就介紹到這了,更多相關C++實現(xiàn)字符串轉(zhuǎn)為整數(shù)內(nèi)容請搜索腳本之家以前的文章或繼續(xù)瀏覽下面的相關文章希望大家以后多多支持腳本之家!
相關文章
C語言實現(xiàn)從文件讀入一個3*3數(shù)組,并計算每行的平均值
今天小編就為大家分享一篇C語言實現(xiàn)從文件讀入一個3*3數(shù)組,并計算每行的平均值,具有很好的參考價值,希望對大家有所幫助。一起跟隨小編過來看看吧2019-12-12如何使用C語言將數(shù)字、字符等數(shù)據(jù)寫入、輸出到文本文件中
在分析數(shù)據(jù)時,首先要解決數(shù)據(jù)的保存問題,下面這篇文章主要給大家介紹了關于如何使用C語言將數(shù)字、字符等數(shù)據(jù)寫入、輸出到文本文件中的相關資料,文中通過實例代碼介紹的非常詳細,需要的朋友可以參考下2022-06-06C++的靜態(tài)成員變量和靜態(tài)成員函數(shù)詳解
這篇文章主要為大家介紹了C++的靜態(tài)成員變量和靜態(tài)成員函數(shù),具有一定的參考價值,感興趣的小伙伴們可以參考一下,希望能夠給你帶來幫助2021-12-12C++實現(xiàn)拼圖游戲代碼(graphics圖形庫)
這篇文章主要為大家詳細介紹了C++實現(xiàn)拼圖游戲代碼,帶有graphics圖形庫,文中示例代碼介紹的非常詳細,具有一定的參考價值,感興趣的小伙伴們可以參考一下2018-05-05C++11特性小結之decltype、類內(nèi)初始化、列表初始化返回值
這篇文章主要介紹了C++11特性小結之decltype、類內(nèi)初始化、列表初始化返回值,本文通過實例代碼給大家介紹的非常詳細,對大家的學習或工作具有一定的參考借鑒價值,需要的朋友可以參考下2020-05-05