[捕獲列表] (參數(shù)) mutable 或 exception 聲明 -> 返回值類型 {函數(shù)體}
//計(jì)算兩個(gè)值的和
auto func = [](int a, int b) -> int{return a+b;};
//當(dāng)返回值的類型是確定時(shí)，可以忽略返回值
auto func = [](int a, int b){return a + b;};
//調(diào)用
int sum = func(1, 3);

class Labmda
{
public:
    const int test;
    Labmda(int value):test(value)
    {
    }
public:
    int run(int a, int b)
    {
        return a + b + test;
    }
}
int main()
{
    int test = 10;
    auto func = Labmda(test);
    int sum = func.run(1, 3);
}
//使用Lambda 表達(dá)式的寫(xiě)法
int main()
{
    int test = 10;
    auto func = [test](int a, int b){return a + b + test;};
    int sum = func(1, 3);
}

int test = 10;
//編譯報(bào)錯(cuò)，test成員不能修改
auto func = [test](int a, int b){test = 8; return a + b + test;}; 
//編譯正常
auto func = [test](int a, int b)mutable {test = 8; return a + b + test;}; 

int test = 10;
auto func = [=](int a, int b){return a + b + test;};
auto func2 = [test](int a, int b){return a + b + test;};
int sum = func(1, 3); //sum等于14

int test = 10;
auto func = [=](int a, int b){return a + b + test;};
test = 5;
int sum = func(1, 3); //sum還是等于14

int test = 10;
auto func = [&](int a, int b){test = 5; return a + b + test;};
auto func2 = [&test](int a, int b){test = 5; return a + b + test;};
int sum = func(1, 3); //sum等于9，test等于5

int test = 10;
auto func = [&](int a, int b){return a + b + test;};
test = 5;
int sum = func(1, 3); //sum等于9，test等于5