assume cs:code
code segment
;做法一
;-----------------------------
	mov bx,0		;因?yàn)閿?shù)據(jù)來(lái)源和去處的偏移地址相同，用bx同意代替
	mov cx,12
 
 
s:	mov ax,offffh	;因?yàn)樾枰貜?fù)利用ax，所以需要循環(huán)設(shè)置
	mov ds,ax
	mov dl,ds:[bx]	;將數(shù)據(jù)復(fù)制到dx的低8位中
 
	mov ax,0020h
	mov ds,ax
	mov ds:[bx],dl	;將數(shù)據(jù)復(fù)制到指定的內(nèi)存單元中
 
	inc bx			;向下一個(gè)單元移動(dòng)
	loop s
 
;-----------------------------
 
;做法二，上一個(gè)做法需要重復(fù)設(shè)置ds，這里可改進(jìn)
;-----------------------------
	mov ax,0ffffh
	mov ds,ax 
	mov ax 0020h
	mov es,ax 
	mov bx,0
	mov cx,12
 s:	mov dl,ds:[bx]
	mov es:[bx],dl
	inc bx
	loop s
 
;-----------------------------
 
	mov ax,4c00h
	int 21h
 code ends
end

assume cs:code
code segment
start:	        mov ax,cs
	 	mov ds,ax
		mov ax,0020h
		mov es,ax	;設(shè)置復(fù)制數(shù)據(jù)的來(lái)源和去處
 
		mov bx,0
		mov cx,offset last-offset start	  ;設(shè)置代碼的長(zhǎng)度
 
s:		mov al,ds:[bx]
		mov es:[bx],al	;實(shí)現(xiàn)數(shù)據(jù)的轉(zhuǎn)移
		inc bx
last:           loop s
 
		mov ax,4c00h
		int 21h
code ends
end

assume cs:code
code segment
	dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h
	dw 16 dup(0)	;?？臻g的使用
 
start: 	mov ax,cs
		mov ss,ax
		mov sp,30h	;?？臻g是從后往前添加，棧頂指向30h
 
		mov bx,0
		mov cx,8
 
s:		push cs:[bx]
		add bx,2
		loop s		;將數(shù)據(jù)段中的0~15單元中的數(shù)據(jù)壓入棧中
 
		mov bx,0
		mov cx,8
 
s0:		pop cs:[bx]
		add bx,2
		loop s0		;依次出棧8個(gè)字型數(shù)據(jù)
 
		mov ax,4c00h
		int 21h
 
code ends
end start

assume cs:code,ds:data,ss:stack
date segment
	dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h
date ends
stack segment
	dw 16 dup(0)	;?？臻g的使用
stack ends 
code segment
start:	mov ax,stack
		mov ss,ax
		mov sp,20h	;棧開(kāi)始的地址已經(jīng)不包括data段的內(nèi)容，則為20h 
		mov ax,data
		mov ds,ax
 		mov bx,0
		mov cx,8 
s:		push ds:[bx]
		add bx,2
		loop s
 		mov bx,0
		mov cx,8 
s0:		pop ds:[bx]
		add bx,2
		loop s0
 		mov ax,4c00h
		int 21h
code ends 
end start

assume cs:code,ds:data
 data segment
	db 'welcome to masm!'
	db 16 dup(0)
data ends 
;----------------------------------
;做法一
code segment
start:	mov ax,data
		mov ds,ax
		mov si,0	;設(shè)置數(shù)據(jù)來(lái)源的起始位置
		mov di,16	;設(shè)置數(shù)據(jù)去處的起始位置
 
		mov cx,8	;用寄存器進(jìn)行復(fù)制，只需要8次
s:		mov ax,ds:[si]
		mov ds:[di],ax
		add si,2
		add di,2
		loop s 
		mov ax,4c00h
		int 21h
code ends
;----------------------------------
;做法二：只利用一個(gè)寄存器就可以實(shí)現(xiàn) 
code segment
start:	mov ax,data
		mov ds,ax
		mov si,0
 
		mov cx,8
s: 		mov ax,ds:[si]
		mov ds:[si+16],ax
		add si,2
		loop s
 		mov ax,4c00h
		int 21h
code ends
 end start