C語言實(shí)現(xiàn)雙人貪吃蛇游戲?qū)嵗a
更新時間:2021年12月29日 08:53:50 作者:.KEG
大家好,本篇文章主要講的是C語言實(shí)現(xiàn)雙人貪吃蛇游戲?qū)嵗a,感興趣的同學(xué)趕快來看一看吧,對你有幫助的話記得收藏一下,方便下次瀏覽
貪吃蛇雙人小游戲,每局游戲兩分鐘,死亡則直接失敗,若時間結(jié)束,則分高者獲勝。?

?上源代碼:
?
#include <stdio.h>
#include <stdlib.h>
#include <Windows.h>
#include <time.h>
#include<stdbool.h>
#include <conio.h>
#define SNAKESIZE 100
#define MAPWIDTH 118
#define MAPHEIGHT 29
struct { //保存食物坐標(biāo)
int x;
int y;
}food;
struct {
int len;
int x[SNAKESIZE];
int y[SNAKESIZE];
}snake;
struct {
int len;
int x[SNAKESIZE];
int y[SNAKESIZE];
}snake1;
char key = '8';//初始方向向上
char key1 = 'w';
int changeFlag = 0 , changeFlag1 = 0;
int speed=150 , sorce = 0 , sorce1 = 0 , sec=0 , min=2;
void gotoxy(int x, int y)//移動光標(biāo)到指定位置
{
COORD coord;
coord.X = x;
coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}
void MAP()//打印邊框和兩條蛇的起始位置
{
for (int i = 0; i <= MAPWIDTH; i += 2)//打印最上面和最下面兩橫邊框
{
gotoxy(i, 0);
printf("■");
gotoxy(i, MAPHEIGHT);
printf("■");
}
for (int i = 1; i < MAPHEIGHT; i++)//打印最左面和最右面
{
gotoxy(0, i);
printf("■");
gotoxy(MAPWIDTH, i);
printf("■");
}
while (1)//打印一個食物
{
srand((unsigned int)time(NULL));
food.x = rand() % (MAPWIDTH - 4) + 2;
food.y = rand() % (MAPHEIGHT - 2) + 1;
if (food.x % 2 == 0)
break;
}
gotoxy(food.x, food.y);
printf("★");
snake.len = snake1.len = 4;//給兩條蛇的長度賦初值
snake.x[0] = MAPWIDTH / 2 + 31;//然后分別打印兩條蛇身部分
snake.y[0] = MAPHEIGHT / 2;
snake1.x[0] = MAPWIDTH / 2 -31;
snake1.y[0] = MAPHEIGHT / 2;
gotoxy(snake.x[0], snake.y[0]);
printf("■");
gotoxy(snake1.x[0], snake1.y[0]);
printf("●");
for (int i = 1; i < snake.len; i++)
{
snake.x[i] = snake.x[i - 1];
snake.y[i] = snake.y[i - 1]+1;
gotoxy(snake.x[i], snake.y[i]);
printf("■");
snake1.x[i] = snake1.x[i - 1];
snake1.y[i] = snake1.y[i - 1]+1;
gotoxy(snake1.x[i], snake1.y[i]);
printf("●");
}
gotoxy(MAPWIDTH , 0);//把光標(biāo)移走
return;
}
void OPERATION()//操作函數(shù)
{
char pre_key = key , pre_key1 = key1 , s;//保存兩條蛇上一次的方向
if (_kbhit())
{
s = getch();
if(s=='w'||s=='s'||s=='a'||s=='d'||s=='W'||s=='S'||s=='A'||s=='D')
key1=s;
else if(s=='8'||s=='5'||s=='4'||s=='6')
key=s;
}
if (changeFlag == 0)//沒吃到食物
{
gotoxy(snake.x[snake.len - 1], snake.y[snake.len - 1]);
printf(" ");//在蛇尾處輸出空格即擦去蛇尾
}
if (changeFlag1 == 0)
{
gotoxy(snake1.x[snake1.len - 1], snake1.y[snake1.len - 1]);
printf(" ");//在蛇尾處輸出空格即擦去蛇尾
}
//將蛇的每一節(jié)依次向前移動一節(jié)(蛇頭除外)
for (int i = snake.len - 1; i > 0; i--)
{
snake.x[i] = snake.x[i - 1];
snake.y[i] = snake.y[i - 1];
}
for (int i = snake1.len - 1; i > 0; i--)
{
snake1.x[i] = snake1.x[i - 1];
snake1.y[i] = snake1.y[i - 1];
}
//蛇當(dāng)前移動的方向不能和前一次的方向相反,比如蛇往左走的時候不能直接按右鍵往右走
//如果當(dāng)前移動方向和前一次方向相反的話,把當(dāng)前移動的方向改為前一次的方向
if (pre_key == '8' && key == '5')
key = '8';
if (pre_key == '5' && key == '8')
key = '5';
if (pre_key == '4' && key == '6')
key = '4';
if (pre_key == '6' && key == '4')
key = '6';
if (pre_key1 == 'w' && key1 == 's')
key1 = 'w';
if (pre_key1 == 's' && key1 == 'w')
key1 = 's';
if (pre_key1 == 'a' && key1 == 'd')
key1 = 'a';
if (pre_key1 == 'd' && key1 == 'a')
key1 = 'd';
//判斷蛇頭應(yīng)該往哪個方向移動
switch (key)
{
case '4':
snake.x[0] -= 2;//往左
break;
case '6':
snake.x[0] += 2;//往右
break;
case '8':
snake.y[0]--;//往上
break;
case '5':
snake.y[0]++;//往下
break;
}
gotoxy(snake.x[0], snake.y[0]);
printf("■");
changeFlag = 0;
switch (key1)
{
case 'a':
case 'A':
snake1.x[0] -= 2;//往左
break;
case 'd':
case 'D':
snake1.x[0] += 2;//往右
break;
case 'w':
case 'W':
snake1.y[0]--;//往上
break;
case 's':
case 'S':
snake1.y[0]++;//往下
break;
}
gotoxy(snake1.x[0], snake1.y[0]);
printf("●");
changeFlag1 = 0;
gotoxy(MAPWIDTH, 0);
return;
}
void createFood()
{
if (snake.x[0] == food.x && snake.y[0] == food.y)//蛇頭碰到食物
{
//蛇頭碰到食物即為要吃掉這個食物了,因此需要再次生成一個食物
while (1)
{
int a = 1 , b=1;
srand((unsigned int)time(NULL));
food.x = rand() % (MAPWIDTH - 4) + 2;
food.y = rand() % (MAPHEIGHT - 2) + 1;
//隨機(jī)生成的食物不能在蛇的身體上
for (int i = 0; i < snake.len; i++)
{
if (snake.x[i] == food.x && snake.y[i] == food.y)
{
a = 0;
break;
}
}
for (int i = 0; i < snake1.len; i++)
{
if (snake1.x[i] == food.x && snake1.y[i] == food.y)
{
b = 0;
break;
}
}
//隨機(jī)生成的食物不能橫坐標(biāo)為奇數(shù),也不能在蛇身,否則重新生成
if (a==1&&b==1 && food.x % 2 == 0)
break;
}
//繪制食物
gotoxy(food.x, food.y);
printf("★");
snake.len++;//吃到食物,蛇身長度加1
sorce += 10;
speed -= 5;//隨著吃的食物越來越多,速度會越來越快
changeFlag = 1;//很重要,因?yàn)槌缘搅耸澄?,就不用再擦除蛇尾的那一?jié),以此來造成蛇身體增長的效果
}
return;
}
void createFood1()
{
if (snake1.x[0] == food.x && snake1.y[0] == food.y)//蛇頭碰到食物
{
//蛇頭碰到食物即為要吃掉這個食物了,因此需要再次生成一個食物
while (1)
{
int a = 1 , b=1;
srand((unsigned int)time(NULL));
food.x = rand() % (MAPWIDTH - 4) + 2;
food.y = rand() % (MAPHEIGHT - 2) + 1;
//隨機(jī)生成的食物不能在蛇的身體上
for (int i = 0; i < snake.len; i++)
{
if (snake.x[i] == food.x && snake.y[i] == food.y)
{
a = 0;
break;
}
}
for (int i = 0; i < snake1.len; i++)
{
if (snake1.x[i] == food.x && snake1.y[i] == food.y)
{
b = 0;
break;
}
}
//隨機(jī)生成的食物不能橫坐標(biāo)為奇數(shù),也不能在蛇身,否則重新生成
if (a==1&&b==1&& food.x % 2 == 0)
break;
}
//繪制食物
gotoxy(food.x, food.y);
printf("★");
snake1.len++;//吃到食物,蛇身長度加1
sorce1 += 10;
speed -= 5;//隨著吃的食物越來越多,速度會越來越快
changeFlag1 = 1;//很重要,因?yàn)槌缘搅耸澄?,就不用再擦除蛇尾的那一?jié),以此來造成蛇身體增長的效果
}
return;
}
bool check()
{
//蛇頭碰到上下邊界,游戲結(jié)束
if (snake.y[0] == 0 || snake.y[0] == MAPHEIGHT)
return true;
//蛇頭碰到左右邊界,游戲結(jié)束
if (snake.x[0] == 0 || snake.x[0] == MAPWIDTH)
return true;
//蛇頭碰到蛇身,游戲結(jié)束
for (int i = 1; i < snake.len; i++)
{
if (snake.x[i] == snake.x[0] && snake.y[i] == snake.y[0])
return true;
}
for (int i = 0; i < snake1.len; i++)
{
if(snake1.x[i] == snake.x[0]&&snake1.y[i] == snake.y[0])
return true;
}
return false;
}
bool check1()
{
//蛇頭碰到上下邊界,游戲結(jié)束
if (snake1.y[0] == 0 || snake1.y[0] == MAPHEIGHT)
return true;
//蛇頭碰到左右邊界,游戲結(jié)束
if (snake1.x[0] == 0 || snake1.x[0] == MAPWIDTH)
return true;
//蛇頭碰到蛇身,游戲結(jié)束
for (int i = 1; i < snake1.len; i++)
{
if (snake1.x[i] == snake1.x[0] && snake1.y[i] == snake1.y[0])
return true;
}
for (int i = 0; i < snake.len; i++)
{
if (snake.x[i] == snake1.x[0] && snake.y[i] == snake1.y[0])
return true;
}
return false;
}
void MENU ()//打印菜單界面
{
printf("\n\n\n\n\t\t\t\t ╔═══════════════════════════════════════╗\n");
printf("\t\t\t\t ║ ║\n");
printf("\t\t\t\t ║ 歡迎來到貪吃蛇 ║\n");
printf("\t\t\t\t ║ ║\n");
printf("\t\t\t\t ║ ║\n");
printf("\t\t\t\t ║ ┏━━┓ ┏━━┓ ┏━━┓ ║\n");
printf("\t\t\t\t ║ 開始:┃ 1┃ 規(guī)則:┃ 2┃ 退出:┃ 3┃ ║\n");
printf("\t\t\t\t ║ ┗━━┛ ┗━━┛ ┗━━┛ ║\n");
printf("\t\t\t\t ║ ║\n");
printf("\t\t\t\t ║ ║\n");
printf("\t\t\t\t ╚═══════════════════════════════════════╝\n");
switch(getch()){
case '1':
system("cls");
START();
break;
case '2':
system("cls");
RULE();
MENU();
break;
case '3':
exit(0);
break;
default:
system("cls");
printf("error");
MENU();
}
}
void RULE ()
{
system("cls");//清屏
printf("\t╔══════════════════════════════════════════════════════════════════════════════════════════════════╗\n");
printf("\t║本游戲玩家一(左側(cè))通過按鍵W、S、A、D(不區(qū)分大小寫)四個鍵分別控制snake1上移、下移、左移和右移。║\n");
printf("\t║玩家二(右側(cè))過按鍵8、5、4、6 四個鍵分別控制snake2上移、下移、左移和右移。 ║\n");
printf("\t║每局游戲兩分鐘,死亡則直接失敗,若時間結(jié)束,則分高者獲勝。 ║\n");
printf("\t╚══════════════════════════════════════════════════════════════════════════════════════════════════╝\n");
system("pause");//暫停
system("cls");//清屏
}
void START()
{
time_t time_sec = 0;
time_t old_sec = 0;
MAP();
system("pause");
time(&time_sec); //獲取時間
old_sec = time_sec; //保存時間
while (!check()&&!check1())
{
OPERATION();
createFood();
createFood1();
Sleep(speed);
time(&time_sec); //獲取秒數(shù)保存到time_t變量
if(time_sec != old_sec) //如果秒數(shù)改變(計(jì)時達(dá)到1秒)
{
old_sec = time_sec; //更新舊的秒數(shù)
if(sec > 0)
sec--; //計(jì)時秒數(shù)減1
else
{
sec = 59; //如果原秒數(shù)為0,則變?yōu)?9
min--; //計(jì)時分鐘減1
}
}
if(min==0&&sec==0)
break;
if(sec>=8)
printf("\a");
gotoxy(4,1);
printf("倒計(jì)時——%02d:%02d\r",min, sec);
}
system("cls");
printf("\n\n\t\t\tGame Over!\n");
system("pause");
}
void OVER ()
{
system("cls");
printf("\n\n\n\n\t\t\t\t╔═══════════════════════════════════════════╗\n");
printf("\t\t\t\t║ ║\n");
printf("\t\t\t\t║ 游戲結(jié)束 ║\n");
printf("\t\t\t\t║ ║\n");
printf("\t\t\t\t║ ║\n");
if(check()&&!check1())
printf("\t\t\t\t║ 玩家一(左側(cè))獲勝,玩家二(右側(cè))失敗。 ║\n");
else if(!check()&&check1())
printf("\t\t\t\t║ 玩家一(左側(cè))失敗,玩家二(右側(cè))獲勝。 ║\n");
else
{
printf("\t\t\t\t║ 玩家一本次游戲得分為:%4d ║\n", sorce1);
printf("\t\t\t\t║ 玩家二本次游戲得分為:%4d ║\n", sorce);
if(sorce>sorce1)
printf("\t\t\t\t║ 玩家一(左側(cè))失敗,玩家二(右側(cè))獲勝。 ║\n");
else if(sorce1>sorce)
printf("\t\t\t\t║ 玩家一(左側(cè))獲勝,玩家二(右側(cè))失敗。 ║\n");
else
printf("\t\t\t\t║ 恭喜你們平局了! ║\n");
}
printf("\t\t\t\t║ ║\n");
printf("\t\t\t\t║ ║\n");
printf("\t\t\t\t╚═══════════════════════════════════════════╝\n");
}
int main ()
{
system("title 雙人貪吃蛇");
system("color F0");
MENU();
OVER();
return 0;
}
[點(diǎn)擊并拖拽以移動]
?


到此這篇關(guān)于C語言實(shí)現(xiàn)雙人貪吃蛇游戲?qū)嵗a的文章就介紹到這了,更多相關(guān)C語言貪吃蛇游戲內(nèi)容請搜索腳本之家以前的文章或繼續(xù)瀏覽下面的相關(guān)文章希望大家以后多多支持腳本之家!
相關(guān)文章
STL區(qū)間成員函數(shù)及區(qū)間算法總結(jié)
這篇文章主要匯總介紹了STL區(qū)間成員函數(shù)及區(qū)間算法,有需要的小伙伴可以參考下。2015-07-07
詳解C語言中的wait()函數(shù)和waitpid()函數(shù)
這篇文章主要介紹了C語言中的wait()函數(shù)和waitpid()函數(shù),注意其在中斷進(jìn)程方面用法的不同,需要的朋友可以參考下2015-08-08
vc6.0中c語言控制臺程序中的定時技術(shù)(定時器)
這篇文章主要介紹了vc6.0中c語言控制臺程序中的定時技術(shù)(定時器),需要的朋友可以參考下2014-04-04
關(guān)于C++面向?qū)ο笤O(shè)計(jì)的訪問性問題詳解
這篇文章主要給大家介紹了關(guān)于C++面向?qū)ο笤O(shè)計(jì)的訪問性問題的相關(guān)資料,文中通過示例代碼介紹的非常詳細(xì),對大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價值,需要的朋友們下面隨著小編來一起學(xué)習(xí)學(xué)習(xí)吧。2017-09-09

