#include <stdio.h>
int main()
{
    int i = 1;
    int n = 0;
    int jieceng = 1;
    scanf("%d", &n);                      //輸入想得到的階層數(shù)
    while (i <= n)
    {
        jieceng *= i;
        i++;
    }
    printf("%d的階層是%d\n", n, jieceng);
    return 0;
}

do……while實(shí)現(xiàn)

#include <stdio.h>
int main()
{
    int i = 1;
    int n = 0;
    int jieceng = 1;
    scanf("%d", &n);
    do
    {
        jieceng *= i;
        i++;
 
    } while (i <= n);
    printf("%d的階層是%d\n", n, jieceng);
    return 0;
}

for實(shí)現(xiàn)

#include <stdio.h>
int main()
{
    int i = 1;
    int n = 0;
    int jieceng = 1;
    scanf("%d", &n);
    for (i = 1; i <= n; i++)
    {
        jieceng *= i;
    }
    printf("%d的階層是%d\n", n, jieceng);
    return 0;
}

2.連續(xù)乘層相加實(shí)現(xiàn)

2.1理論步驟

首先明確要連續(xù)相加，必然需要2層循環(huán)嵌套

2.2實(shí)踐結(jié)果

我這里用2層for循環(huán)實(shí)現(xiàn)

#include<stdio.h>
int main()                                         //算1~n階層相加
{
    int sum = 0;
    int jiecen = 0;
    int i = 0;
    int j = 0;
    int n = 0;
    scanf("%d", &n);                               //設(shè)置想要到達(dá)的n值
    for (j = 1; j <= n; j++)
    {
        for (i = 1, jiecen =1; i <= j; i++)         //重置jieceng，使每次從1開(kāi)始
        {
            jiecen = jiecen * i;                   //里循環(huán)得每一相應(yīng)階層數(shù)
        }
        sum += jiecen;                             //階層之和
    }
    printf("%d\n", sum);
    return 0;
}

一層for循環(huán)實(shí)現(xiàn)（簡(jiǎn)潔版）

#include <stdio.h>
int main()                                         //算1~10階層相加(j簡(jiǎn)短版）好**
{
    int sum = 0;
    int jiecen = 1;
    int i = 0;
    int n = 0;
    scanf("%d", &n);
    for (i = 1; i <= n; i++)
    {
        jiecen = jiecen * i;
        sum += jiecen;
    }
    printf("%d\n", sum);
    return 0;
}

以上就是C語(yǔ)言實(shí)現(xiàn)階乘的示例詳解的詳細(xì)內(nèi)容，更多關(guān)于C語(yǔ)言階乘的資料請(qǐng)關(guān)注腳本之家其它相關(guān)文章！

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