PGSQL查詢最近N天的數(shù)據(jù)及SQL語句實現(xiàn)替換字段內容

更新時間：2023年03月06日 08:56:46 作者：兩點王爺

PostgreSQL提供了WITH語句,允許你構造用于查詢的輔助語句,下面這篇文章主要給大家介紹了關于PGSQL查詢最近N天的數(shù)據(jù)及SQL語句實現(xiàn)替換字段內容的相關資料,文中通過實例代碼介紹的非常詳細,需要的朋友可以參考下

1、用SQL查詢最近N天的數(shù)據(jù)

思路：先獲取當前的時間，然后更具當前時間去減去對應的天數(shù)，就可以得到需要的天數(shù)了。然后用這些天數(shù)作為條件，然后即可查詢出需要多少天的數(shù)據(jù)了。

-- 獲取當前時間
SELECT CURRENT_TIMESTAMP;
-- 或
SELECT now();
select CURRENT_TIMESTAMP :: DATE AS "當前日期";
SELECT CURRENT_DATE;
select CURRENT_TIMESTAMP :: TIME AS "當前時間";
SELECT CURRENT_TIME;

最近N天

-- 最近7天
SELECT DATE( T ) AS DAY
FROM
generate_series ( ( CURRENT_TIMESTAMP - INTERVAL '6 day' ) :: DATE,CURRENT_TIMESTAMP :: DATE, '1 days' ) AS T ;

當然6 day、1 day這些也是可修改的；

--統(tǒng)計最近30、7、昨天、今天的數(shù)據(jù)
SELECT
	count(*) AS AllData,
	count(*) filter ( WHERE create_time BETWEEN ( SELECT CURRENT_DATE - INTERVAL '30 day' ) AND CURRENT_DATE ) AS Last30DayData,
	count(*) filter ( WHERE create_time BETWEEN ( SELECT CURRENT_DATE - INTERVAL '7 day' ) AND CURRENT_DATE ) AS Last7DayData,
	count(*) filter ( WHERE create_time BETWEEN ( SELECT CURRENT_DATE - INTERVAL '1 day' ) AND CURRENT_DATE ) AS YesterdayData,
	count(*) filter ( WHERE create_time >= CURRENT_DATE ) AS todayAddData 
FROM
	table_name;

實例如下：查詢lic_plate字段不為空和為空的最近7天的數(shù)據(jù)

-- 查詢lic_plate字段不為空的最近7天的數(shù)據(jù)
select count(tn.lic_plate) AS number,tn.create_time AS percentage
from table_name tn
where tn.create_time in (SELECT DATE(T) AS DAY
                      FROM generate_series((CURRENT_TIMESTAMP - INTERVAL '6 day') :: DATE, CURRENT_TIMESTAMP :: DATE,'1 days') AS T) AND lic_plate is not null
group by tn.create_time order by tn.create_time;
 
-- 查詢lic_plate字段為空的最近7天的數(shù)據(jù)
select count(id)  AS number,CSQV.create_time AS percentage
from  (select * from table_name tn where lic_plate is  null) AS CSQV where CSQV.create_time in (SELECT DATE(T) AS DAY
                      FROM generate_series((CURRENT_TIMESTAMP - INTERVAL '6 day') :: DATE, CURRENT_TIMESTAMP :: DATE,'1 days') AS T)
group by CSQV.create_time;

2、用SQL語句實現(xiàn)替換字段里的內容

思路：使用替換函數(shù)替換即可

-- 替換語句
update 表名 set 替換字段名 = replace(替換字段名,'被替換內容','替換內容');

實例如下：將 my_test 表的 test_content 字段內容進行替換

update my_test set test_content = replace(test_content,'1','18');

替換函數(shù)：如果沒有可以創(chuàng)建，創(chuàng)建函數(shù)如下：

-- replace all occurrences in string of old_substr with new_substr 
-- auto-generated definition
create function replace(text, text, text) returns text
    immutable
    strict
    cost 1
    language internal
as
$$begin
-- missing source code
end;$$;
 
 
comment on function replace(text, text, text) is 'replace all occurrences in string of old_substr with new_substr';

3、SQL將查詢結果賦值

--查詢表數(shù)據(jù)，給test_content字段并賦值
select test_id,test_code,'測試數(shù)據(jù)' test_content from my_test;
--查詢表數(shù)據(jù)給自定義 ABCD字段 并賦值
select test_id,test_code,'測試數(shù)據(jù)' ABCD from my_test;

4、SQL查詢字段內容為 NULL值時候賦值

select test_id,test_code,COALESCE(test_content,'測試數(shù)據(jù)') ABCD from my_test;
-- ||
select test_id,test_code,
       CASE
           WHEN test_content IS NOT NULL THEN test_content
           ELSE '測試數(shù)據(jù)'
           END ABCD from my_test;