import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * 大數(shù)乘法的簡(jiǎn)單實(shí)現(xiàn), 目前還不是很完善
 * Fix:
 * 1. 修改前后刪除0的一些錯(cuò)誤情況
 * 2. 支持負(fù)數(shù)運(yùn)算
 * 3. 判斷輸入字符串是否符合小數(shù)定義, 用正則表達(dá)式判斷
 * @author icejoywoo
 * @since 2012.2.16
 * @version 0.1.1
 */
public class BigNumber {
    public static void main(String[] args) throws IOException {
        System.out.println("Input two large integers:");
        BufferedReader buffer = new BufferedReader(new InputStreamReader(System.in));
        String[] strArray = buffer.readLine().split("\\*");
        System.out.println(bigNumberMultiply(strArray[0], strArray[1]));
    }

    /**
     * 計(jì)算兩個(gè)任意大小和精度的數(shù)的乘積
     * @param first 第一個(gè)參數(shù)
     * @param second 第二個(gè)參數(shù)
     * @return 兩個(gè)數(shù)的乘積
     */
    private static String bigNumberMultiply(String first, String second) {
        // 正負(fù)號(hào)判斷標(biāo)志
        boolean flag = false;

        if (first.charAt(0) == '-') {
            flag = !flag;
            first = first.substring(1);
        }

        if (second.charAt(0) == '-') {
            flag = !flag;
            second = second.substring(1);
        }

        // 小數(shù)點(diǎn)的位置
        int aPoints = first.length() - first.indexOf('.') - 1;
        int bPoints = second.length() - second.indexOf('.') - 1;
        int pointPos = aPoints + bPoints; // 結(jié)果的小數(shù)點(diǎn)位置

        // 刪除小數(shù)點(diǎn)
        StringBuffer aBuffer = new StringBuffer(first.replaceAll("\\.", ""));
        StringBuffer bBuffer = new StringBuffer(second.replaceAll("\\.", ""));

        int[] a = string2IntArray(aBuffer.toString());
        int[] b = string2IntArray(bBuffer.toString());

        int[] result = new int[a.length + b.length - 1]; // 保存結(jié)果的數(shù)組

        // 計(jì)算
        for (int i = 0; i < a.length; i++) {
            for (int j = 0; j < b.length; j++) {
                result[i + j] += a[i] * b[j];
            }
        }

        // result中的某一位大于9的話需要進(jìn)位
        for (int i = result.length - 1; i >= 0; --i) {
            if (result[i] > 9) {
                result[i - 1] += result[i] / 10;
                result[i] = result[i] % 10;
            }
        }

        StringBuffer buffer = new StringBuffer(); // 將result數(shù)組轉(zhuǎn)換為字符串
        for (int i = 0; i < result.length; ++i) {
            // 添加小數(shù)點(diǎn)
            if(result.length - i == pointPos) {
                buffer.append(".");
            }
            buffer.append(String.valueOf(result[i]));
        }

        if (buffer.indexOf(".") != -1)
        {
            // 刪除最開始的0
            int i = 0;
            while (i < buffer.length()) {
                if (buffer.length() > 2 && buffer.charAt(i+1) == '.') { // 小數(shù)點(diǎn)前只有一個(gè)數(shù) 0.
                    break;
                } else if (buffer.charAt(i) == '0') { // 刪除最前邊的0
                    buffer.deleteCharAt(i);
                    i = 0;
                    continue;
                } else { // 當(dāng)?shù)谝晃徊皇?的時(shí)候
                    break;
                }
            }

            // 刪除末尾的0
            i = buffer.length() - 1;
            while (i >= 0) {
                if (buffer.length() > 2 && buffer.charAt(i-1) == '.') { // 小數(shù)點(diǎn)后直接是數(shù)字
                    break;
                } else if (buffer.charAt(i) == '0') { // 刪除末尾的0
                    buffer.deleteCharAt(i);
                    i = buffer.length() - 1;
                    continue;
                } else { // 當(dāng)最后一位不是0的時(shí)候
                    break;
                }
            }
        }

        // 根據(jù)符號(hào)位, 返回值的正負(fù)標(biāo)志
        if (flag) {
            return "-" + buffer.toString();
        } else {
            return buffer.toString();
        }
    }

    /**
     * 將字符串裝換為數(shù)組
     * @param number
     * @return
     */
    private static int[] string2IntArray(String number) {
        // 判斷輸入是否符合浮點(diǎn)數(shù)的要求
        Pattern pattern = Pattern.compile("^(-?\\d+|\\d*)\\.?\\d*$");
        Matcher matcher = pattern.matcher(number);
        if (!matcher.find()) {
            throw new IllegalArgumentException("輸入的數(shù)不正確!");
        }

        int[] result = new int[number.length()];
        for (int i = 0; i < number.length(); i++) {
            result[i] = (int) (number.charAt(i) - '0');
        }
        return result;
    }
}

Input two large integers:
1a*a22
Exception in thread "main" java.lang.IllegalArgumentException: 輸入的數(shù)不正確!
at BigNumber.string2IntArray(BigNumber.java:132)
at BigNumber.bigNumberMultiply(BigNumber.java:54)
at BigNumber.main(BigNumber.java:22)

Input two large integers:
-23424.2300*02345.23400000
-54935300.61982

Python 2.6.5
>>> -23424.2300*02345.23400000
-54935300.619819999