ASP BASE64加解密(親測可用)
更新時間:2014年07月17日 08:52:31 投稿:mdxy-dxy
之前腳本之家小編已經(jīng)為大家分享了了幾個asp BASE64加解密函數(shù)代碼,不過實際用的過程中都有這樣或那樣的問題,現(xiàn)在重新整理一個
核心代碼:
<% ' OPTION EXPLICIT const BASE_64_MAP_INIT = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" dim newline dim Base64EncMap(63) dim Base64DecMap(127) '初始化函數(shù) PUBLIC SUB initCodecs() ' 初始化變量 newline = "<P>" & chr(13) & chr(10) dim max, idx max = len(BASE_64_MAP_INIT) for idx = 0 to max - 1 Base64EncMap(idx) = mid(BASE_64_MAP_INIT, idx + 1, 1) next for idx = 0 to max - 1 Base64DecMap(ASC(Base64EncMap(idx))) = idx next END SUB 'Base64加密函數(shù) PUBLIC FUNCTION base64Encode(plain) if len(plain) = 0 then base64Encode = "" exit function end if dim ret, ndx, by3, first, second, third by3 = (len(plain) \ 3) * 3 ndx = 1 do while ndx <= by3 first = asc(mid(plain, ndx+0, 1)) second = asc(mid(plain, ndx+1, 1)) third = asc(mid(plain, ndx+2, 1)) ret = ret & Base64EncMap( (first \ 4) AND 63 ) ret = ret & Base64EncMap( ((first * 16) AND 48) + ((second \ 16) AND 15 ) ) ret = ret & Base64EncMap( ((second * 4) AND 60) + ((third \ 64) AND 3 ) ) ret = ret & Base64EncMap( third AND 63) ndx = ndx + 3 loop if by3 < len(plain) then first = asc(mid(plain, ndx+0, 1)) ret = ret & Base64EncMap( (first \ 4) AND 63 ) if (len(plain) MOD 3 ) = 2 then second = asc(mid(plain, ndx+1, 1)) ret = ret & Base64EncMap( ((first * 16) AND 48) + ((second \ 16) AND 15 ) ) ret = ret & Base64EncMap( ((second * 4) AND 60) ) else ret = ret & Base64EncMap( (first * 16) AND 48) ret = ret '& "=" end if ret = ret '& "=" end if base64Encode = ret END FUNCTION 'Base64解密函數(shù) PUBLIC FUNCTION base64Decode(scrambled) if len(scrambled) = 0 then base64Decode = "" exit function end if dim realLen realLen = len(scrambled) do while mid(scrambled, realLen, 1) = "=" realLen = realLen - 1 loop dim ret, ndx, by4, first, second, third, fourth ret = "" by4 = (realLen \ 4) * 4 ndx = 1 do while ndx <= by4 first = Base64DecMap(asc(mid(scrambled, ndx+0, 1))) second = Base64DecMap(asc(mid(scrambled, ndx+1, 1))) third = Base64DecMap(asc(mid(scrambled, ndx+2, 1))) fourth = Base64DecMap(asc(mid(scrambled, ndx+3, 1))) ret = ret & chr( ((first * 4) AND 255) + ((second \ 16) AND 3)) ret = ret & chr( ((second * 16) AND 255) + ((third \ 4) AND 15)) ret = ret & chr( ((third * 64) AND 255) + (fourth AND 63)) ndx = ndx + 4 loop if ndx < realLen then first = Base64DecMap(asc(mid(scrambled, ndx+0, 1))) second = Base64DecMap(asc(mid(scrambled, ndx+1, 1))) ret = ret & chr( ((first * 4) AND 255) + ((second \ 16) AND 3)) if realLen MOD 4 = 3 then third = Base64DecMap(asc(mid(scrambled,ndx+2,1))) ret = ret & chr( ((second * 16) AND 255) + ((third \ 4) AND 15)) end if end if base64Decode = ret END FUNCTION %>
使用方法:
' 初始化 call initCodecs Response.Write(base64Encode("腳本之家之我要加密的字符串")) Response.Write(base64Decode("bWFyczIwMTAwMjIw0"))
相關(guān)文章
十萬條Access數(shù)據(jù)表分頁的兩個解決方法
后臺數(shù)據(jù)庫用是Access,客戶用了一年后說打開界面非常慢,查看了數(shù)據(jù)庫后發(fā)現(xiàn)數(shù)據(jù)表中的記錄已有五萬多條,自己試過將記錄復(fù)制到10 萬條,打開界面非常慢,翻頁也是同樣的問題2008-06-06對象不支持此屬性或方法: Session.CodePage = 936 解決方法
這篇文章主要介紹了對象不支持此屬性或方法: Session.CodePage = 936 解決方法,需要的朋友可以參考下2015-07-07GetPaing 函數(shù)之a(chǎn)sp采集函數(shù)中用到的獲取分頁的代碼
GetPaing 函數(shù)之a(chǎn)sp采集函數(shù)中用到的獲取分頁的代碼...2007-09-09asp中向文本框輸出數(shù)據(jù)原樣式的函數(shù)
asp中向文本框輸出數(shù)據(jù)原樣式的函數(shù)...2007-03-03asp textbox獲取顯示mysql數(shù)據(jù)示例代碼
這篇文章主要介紹了asp textbox如何獲取顯示mysql數(shù)據(jù),需要的朋友可以參考下2014-05-05