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C#獲取兩個(gè)時(shí)間的時(shí)間差并去除周末(取工作日)的方法

 更新時(shí)間:2015年05月07日 10:42:44   作者:niuniu  
這篇文章主要介紹了C#獲取兩個(gè)時(shí)間的時(shí)間差并去除周末(取工作日)的方法,可有效的實(shí)現(xiàn)獲取工作日的功能,涉及C#時(shí)間操作的相關(guān)技巧,需要的朋友可以參考下

本文實(shí)例講述了C#獲取兩個(gè)時(shí)間的時(shí)間差并去除周末的方法。分享給大家供大家參考。具體分析如下:

一般來(lái)說(shuō)取時(shí)間差的代碼很多,但是能夠只取工作日的時(shí)間差的代碼很少,這段代碼就來(lái)實(shí)現(xiàn)這一功能。

protected void Page_Load(object sender, EventArgs e)
{
 DateTime start = Convert.ToDateTime("2012-12-10");
 DateTime end= Convert.ToDateTime("2012-12-18");
 TimeSpan span = end - start;
 //int totleDay=span.Days;
 //DateTime spanNu = DateTime.Now.Subtract(span);
 int AllDays=Convert.ToInt32(span.TotalDays)+1;//差距的所有天數(shù)
 int totleWeek = AllDays / 7;//差別多少周
 int yuDay = AllDays % 7; //除了整個(gè)星期的天數(shù)
 int lastDay = 0;
 if (yuDay == 0) //正好整個(gè)周
 {
  lastDay = AllDays - (totleWeek * 2);
 }
 else
 {
  int weekDay = 0;
  int endWeekDay = 0; //多余的天數(shù)有幾天是周六或者周日
  switch (start.DayOfWeek)
  {
  case DayOfWeek.Monday:
   weekDay = 1;
   break;
  case DayOfWeek.Tuesday:
   weekDay = 2;
   break;
  case DayOfWeek.Wednesday:
   weekDay = 3;
   break;
  case DayOfWeek.Thursday:
   weekDay = 4;
   break;
  case DayOfWeek.Friday:
   weekDay = 5;
   break;
  case DayOfWeek.Saturday:
   weekDay = 6;
   break;
  case DayOfWeek.Sunday:
   weekDay = 7;
   break;
  }
  if ((weekDay == 6 && yuDay >= 2) || (weekDay == 7 && yuDay >= 1) || (weekDay == 5 && yuDay >= 3) || (weekDay == 4 && yuDay >= 4) || (weekDay == 3 && yuDay >= 5) || (weekDay == 2 && yuDay >= 6) || (weekDay == 1 && yuDay >=7))
  {
  endWeekDay =2;
  }
  if ((weekDay == 6 && yuDay < 1) || (weekDay == 7 && yuDay <5) || (weekDay == 5 && yuDay < 2) || (weekDay == 4 && yuDay < 3) || (weekDay == 3 && yuDay < 4) || (weekDay == 2 && yuDay < 5) || (weekDay == 1 && yuDay < 6))  {
  endWeekDay = 1;
  }
  lastDay = AllDays - (totleWeek * 2) - endWeekDay;
 }
 lblTime.Text = lastDay.ToString();
}

希望本文所述對(duì)大家的C#程序設(shè)計(jì)有所幫助。

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