這里使用jquery實現(xiàn)的表單驗證效果，以Ajax方式驗證你的表單是否填寫正確，如果驗證不通過，會將表單元素背景變成紅色，并給出提示信息，簡單實用，jquery表單驗證功能已經(jīng)有很多了，本款表單驗證特效看上去更簡單，不懂Ajax的朋友，或許直接套用即可實現(xiàn)無刷新表單驗證功能。

運行效果截圖如下：

在線演示地址如下：

http://demo.jb51.net/js/2015/jquery-table-form-check-codes/

具體代碼如下：

<!DOCTYPE html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>jQuery表單驗證</title>
<style type="text/css">
body, input, textarea {
 font-size:12px;
 line-height:18px;
 font-family:Verdana, Geneva, sans-serif;
}
input {width:200px;}
.submit {width:120px;}
#error {
 color:red;
 font-size:10px;
 display:none;
}
.needsfilled {
 background:red;
 color:white;
}
</style>
<script type="text/javascript" src="jquery-1.6.2.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
 // Place ID's of all required fields here.
 required = ["name", "email", "message"];
 // If using an ID other than #email or #error then replace it here
 email = $("#email");
 errornotice = $("#error");
 // The text to show up within a field when it is incorrect
 emptyerror = "Please fill out this field.";
 emailerror = "Please enter a valid e-mail.";
 $("#theform").submit(function(){ 
  //Validate required fields
  for (i=0;i<required.length;i++) {
   var input = $('#'+required[i]);
   if ((input.val() == "") || (input.val() == emptyerror)) {
    input.addClass("needsfilled");
    input.val(emptyerror);
    errornotice.fadeIn(750);
   } else {
    input.removeClass("needsfilled");
   }
  }
  // Validate the e-mail.
  if (!/^([a-zA-Z0-9_\.\-])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/.test(email.val())) {
   email.addClass("needsfilled");
   email.val(emailerror);
  }
  //if any inputs on the page have the class 'needsfilled' the form will not submit
  if ($(":input").hasClass("needsfilled")) {
   return false;
  } else {
   errornotice.hide();
   return true;
  }
 });
 // Clears any fields in the form when the user clicks on them
 $(":input").focus(function(){  
  if ($(this).hasClass("needsfilled") ) {
   $(this).val("");
   $(this).removeClass("needsfilled");
  }
 });
}); 
</script>
</head>
<body>
<form action="mail.php" id="theform" name="theform" method="post">
 <p><label for="name">Name</label><br /><input id="name" type="text" value="" name="name" /></p>
 <p><label for="email">E-mail</label><br /><input id="email" type="text" value="" name="email" /></p>
 <p><label for="message">Message</label><br /><textarea id="message" rows="7" cols="30" name="message"></textarea></p>
 <p><input class="submit" type="submit" name="submit" value="Submit Form" /></p>
 <p id="error">表單中有錯誤信息！</p>
</form>
</body>
</html>

希望本文所述對大家的jquery程序設計有所幫助。

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