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asp將本地的文件上傳到服務器

 更新時間：2022年05月06日 15:17:02   投稿：lijiao  
如果你想把自己機器的圖片或者文件放到服務器上該怎么辦呢？<BR>可選有三種辦法ftp上傳、用u盤拷貝到服務器上、如果服務器支持asp上傳功能，用網頁瀏覽器將文件上傳到服務器上

今天我們講解如何利用asp的上傳功能將本地的文件上傳到服務器上。

最簡系統(tǒng)包括下面三個文件：

upload.htm       --上傳口文件，選擇本地文件
uploadimg.asp    --上傳程序控制文件
upload_5xsoft.inc   --無組件上傳類，此文件初學者不用學習，只要會用就可以了

upload.htm內容————上傳口文件，選擇本地文件

<html>
<head>
</head>

<body>
<table width="80%" border="0" align="center">
<form name="form1" method="post" action="uploadimg.asp" enctype="multipart/form-data">
<tr>
  <td align="center"><input name="upfile" type="file" id="upfile"></td>
 </tr>
   <tr>
  <td align="center"><input type="submit" name="Submit" value="上傳圖片"></td>
 </tr>
 </form>
</table>
</body>
</html>

uploadimg.asp內容————上傳程序控制文件

<!--#include FILE="upload_5xsoft.inc"-->
<%
dim upload,file,filepath
filepath="UPLOAD/"
set upload=new upload_5xSoft ''建立上傳對象
for each formName in upload.file ''列出所有上傳了的文件
 set file=upload.file(formName) ''生成一個文件對象
 if file.FileSize>0 then     ''如果 FileSize > 0 說明有文件數據
 fname = file.filename
 file.SaveAs Server.mappath(filepath&fname)  ''保存文件
 end if
set file=nothing
next
set upload=nothing ''刪除此對象

upload_5xsoft.inc內容————此文件內容不屬于本演練程序內容，本演練應用此類的方法

<SCRIPT RUNAT=SERVER LANGUAGE=VBSCRIPT>
dim oUpFileStream

Class upload_5xSoft
 
dim Form,File,Version
 
Private Sub Class_Initialize 
dim RequestBinDate,sStart,bCrLf,sInfo,iInfoStart,iInfoEnd,tStream,iStart,oFileInfo
dim iFileSize,sFilePath,sFileType,sFormvalue,sFileName
dim iFindStart,iFindEnd
dim iFormStart,iFormEnd,sFormName
Version="無組件上傳類 Version 0.93"
set Form=Server.CreateObject("Scripting.Dictionary")
set File=Server.CreateObject("Scripting.Dictionary")
if Request.TotalBytes<1 then Exit Sub
set tStream = Server.CreateObject("adodb.stream")
set oUpFileStream = Server.CreateObject("adodb.stream")
oUpFileStream.Type = 1
oUpFileStream.Mode =3
oUpFileStream.Open
oUpFileStream.Write Request.BinaryRead(Request.TotalBytes)
Response.Write "<font size=""2"">頁面執(zhí)行時間："&FormatNumber((Timer() -time1)*1000,3)&"毫秒</font><br>"
oUpFileStream.Position=0
RequestBinDate =oUpFileStream.Read 
iFormStart = 1
iFormEnd = LenB(RequestBinDate)
bCrLf = chrB(13) & chrB(10)
sStart = MidB(RequestBinDate,1, InStrB(iFormStart,RequestBinDate,bCrLf)-1)
iStart = LenB (sStart)
iFormStart=iFormStart+iStart+1
while (iFormStart + 10) < iFormEnd 
 iInfoEnd = InStrB(iFormStart,RequestBinDate,bCrLf & bCrLf)+3
 tStream.Type = 1
 tStream.Mode =3
 tStream.Open
 oUpFileStream.Position = iFormStart
 oUpFileStream.CopyTo tStream,iInfoEnd-iFormStart
 tStream.Position = 0
 tStream.Type = 2
 tStream.Charset ="gb2312"
 sInfo = tStream.ReadText   
 '取得表單項目名稱
 iFormStart = InStrB(iInfoEnd,RequestBinDate,sStart)
 iFindStart = InStr(22,sInfo,"name=""",1)+6
 iFindEnd = InStr(iFindStart,sInfo,"""",1)
 sFormName = Mid (sinfo,iFindStart,iFindEnd-iFindStart)
 '如果是文件
 if InStr (45,sInfo,"filename=""",1) > 0 then
 set oFileInfo=new FileInfo
 '取得文件名
 iFindStart = InStr(iFindEnd,sInfo,"filename=""",1)+10
 iFindEnd = InStr(iFindStart,sInfo,"""",1)
 sFileName = Mid (sinfo,iFindStart,iFindEnd-iFindStart)
 oFileInfo.FileName=getFileName(sFileName)
 oFileInfo.FilePath=getFilePath(sFileName)
 '取得文件類型
 iFindStart = InStr(iFindEnd,sInfo,"Content-Type: ",1)+14
 iFindEnd = InStr(iFindStart,sInfo,vbCr)
 oFileInfo.FileType =Mid (sinfo,iFindStart,iFindEnd-iFindStart)
 oFileInfo.FileStart =iInfoEnd
 oFileInfo.FileSize = iFormStart -iInfoEnd -3
 oFileInfo.FormName=sFormName
 file.add sFormName,oFileInfo
 else
 '如果是表單項目
 tStream.Close
 tStream.Type =1
 tStream.Mode =3
 tStream.Open
 oUpFileStream.Position = iInfoEnd 
 oUpFileStream.CopyTo tStream,iFormStart-iInfoEnd-3
 tStream.Position = 0
 tStream.Type = 2
 tStream.Charset ="gb2312"
 sFormvalue = tStream.ReadText 
 form.Add sFormName,sFormvalue
 end if
 tStream.Close
 iFormStart=iFormStart+iStart+1
 wend
RequestBinDate=""
set tStream =nothing
End Sub

Private Sub Class_Terminate 
if not Request.TotalBytes<1 then
 form.RemoveAll
 file.RemoveAll
 set form=nothing
 set file=nothing
 oUpFileStream.Close
 set oUpFileStream =nothing
 end if
End Sub
  
 
 Private function GetFilePath(FullPath)
 If FullPath <> "" Then
  GetFilePath = left(FullPath,InStrRev(FullPath, ""))
 Else
  GetFilePath = ""
 End If
 End function
 
 Private function GetFileName(FullPath)
 If FullPath <> "" Then
  GetFileName = mid(FullPath,InStrRev(FullPath, "")+1)
 Else
  GetFileName = ""
 End If
 End function

End Class

Class FileInfo
 dim FormName,FileName,FilePath,FileSize,FileType,FileStart
 Private Sub Class_Initialize 
  FileName = ""
  FilePath = ""
  FileSize = 0
  FileStart= 0
  FormName = ""
  FileType = ""
 End Sub
 
 Public function SaveAs(FullPath)
  dim oFileStream,ErrorChar,i
  SaveAs=1
  if trim(fullpath)="" or right(fullpath,1)="/" then exit function
  set oFileStream=CreateObject("Adodb.Stream")
  oFileStream.Type=1
  oFileStream.Mode=3
  oFileStream.Open
  oUpFileStream.position=FileStart
  oUpFileStream.copyto oFileStream,FileSize
  oFileStream.SaveToFile FullPath,2
  oFileStream.Close
  set oFileStream=nothing 
  SaveAs=0
 end function
End Class
</SCRIPT>

此文所訴的內容是上傳文件的最簡化程式，請朋友們自己分析一下，學會本演練，asp一般的上傳功能就基本掌握了。

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