日期(exportDate)        數(shù)量(amount) 
--------------          ----------- 
14-2月 -08            20 
10-3月 -08            2 
14-4月 -08            6 
14-6月 -08            75 
24-10月-09           23 
14-11月-09           45 
04-8月 -10            5 
04-9月 -10            44 
04-10月-10           88

注意：為了顯示更直觀，如下查詢已皆按相應(yīng)分組排序

1.按年份分組

select to_char(exportDate,'yyyy'),sum(amount) from table1 group by to_char(exportDate,'yyyy');

年份   數(shù)量 
----------------------------- 
2009  68 
2010  137 
2008  103

2.按月份分組

select to_char(exportDate,'yyyy-mm'),sum(amount) from table1 group by to_char(exportDate,'yyyy-mm')
order by to_char(exportDate,'yyyy-mm');

月份      數(shù)量 
----------------------------- 
2008-02  20 
2008-03  2 
2008-04  6 
2008-06  75 
2009-10  23 
2009-11  45 
2010-08  5 
2010-09  44 
2010-10  88

3.按季度分組

select to_char(exportDate,'yyyy-Q'),sum(amount) from table1 group by to_char(exportDate,'yyyy-Q') 
order by to_char(exportDate,'yyyy-Q');

季度     數(shù)量 
------------------------------ 
2008-1  22 
2008-2  81 
2009-4  68 
2010-3  49 
2010-4  88

4.按周分組

select to_char(exportDate,'yyyy-IW'),sum(amount) from table1 group by to_char(exportDate,'yyyy-IW')
order by to_char(exportDate,'yyyy-IW');

周       數(shù)量 
------------------------------ 
2008-07  20 
2008-11  2 
2008-16  6 
2008-24  75 
2009-43  23 
2009-46  45 
2010-31  5 
2010-35  44 
2010-40  88

PS：Oracle按時(shí)間段分組統(tǒng)計(jì)
想要按時(shí)間段分組查詢，首先要了解level,connect by,oracle時(shí)間的加減.
關(guān)于level這里不多說(shuō)，我只寫出一個(gè)查詢語(yǔ)句:

----level 是一個(gè)偽例 
 select level from dual connect by level <=10 
 ---結(jié)果：
1   
2 
3 
4 
5 
6 
7 
8 
9 
10

oracle時(shí)間的加減看看試一下以下sql語(yǔ)句就會(huì)知道:

select sysdate -1 from dual 
----結(jié)果減一天,也就24小時(shí) 
select sysdate-(1/2) from dual 
-----結(jié)果減去半天，也就12小時(shí) 
select sysdate-(1/24) from dual 
-----結(jié)果減去1 小時(shí) 
select sysdate-((1/24)/12) from dual  
----結(jié)果減去5分鐘 
select sydate-(level-1) from dual connect by level<=10 
---結(jié)果是10間隔1天的時(shí)間

下面是本次例子：

select dt, count(satisfy_degree) as num from T_DEMO i , 
(select sysdate - (level-1) * 2 dt 
from dual connect by level <= 10) d 
where i.satisfy_degree='satisfy_1' and 
i.insert_time<dt and i.insert_time> d.dt-2 
group by d.dt

例子中的sysdate - (level-1) * 2得到的是一個(gè)間隔是2天的時(shí)間
group by d.dt 也就是兩天的時(shí)間間隔分組查詢

自己實(shí)現(xiàn)例子：

create table A_HY_LOCATE1
(
 MOBILE_NO     VARCHAR2(32),
 LOCATE_TYPE    NUMBER(4),
 AREA_NO      VARCHAR2(32),
 CREATED_TIME    DATE,
 AREA_NAME     VARCHAR2(512),
)；

select (sysdate-13)-(level-1)/4 from dual connect by level<=34 --從第一條時(shí)間記錄開(kāi)始（sysdate-13）為表中的最早的日期，“34”出現(xiàn)的分組數(shù)（一天按每六個(gè)小時(shí)分組就應(yīng)該為4）

一下是按照每6個(gè)小時(shí)分組

select mobile_no,area_name,max(created_time ),dt, count(*) as num from a_hy_locate1 i ,
(select (sysdate-13)-(level-1)/4 dt
from dual connect by level <= 34) d
where i.locate_type = 1 and
i.created_time<dt and i.created_time> d.dt-1/4
group by mobile_no,area_name,d.dt

另外一個(gè)方法：

--按六小時(shí)分組
select trunc(to_number(to_char(created_time, 'hh24')) / 6),count(*)
 from t_test
 where created_time > trunc(sysdate - 40)
 group by trunc(to_number(to_char(created_time, 'hh24')) / 6)


--按12小時(shí)分組
select trunc(to_number(to_char(created_time, 'hh24')) / 6),count(*)
 from t_test
 where created_time > trunc(sysdate - 40)
 group by trunc(to_number(to_char(created_time, 'hh24')) / 6)

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