select years,(select amount from Tb_Amount as A where month=1 and A.years=Tb_Amount.years)as m1,
(select amount from Tb_Amount as A where month=2 and A.years=Tb_Amount.years)as m2,
(select amount from Tb_Amount as A where month=3 and A.years=Tb_Amount.years)as m3
from Tb_Amount group by years

select years as 年份,
sum(case when month='1' then amount end) as 一月,
 sum(case when month='2' then amount end) as 二月,
sum(case when month='3' then amount end) as 三月
from dbo.Tb_Amount group by years order by years desc

select uname as 姓名,
SUM(case when era='年輕' then amount end) as 年輕,
SUM(case when era='中年' then amount end) as 中年,
SUM(case when era='老年' then amount end) as 老年
from Tb_People group by uname order by uname desc

select sname as 姓名,
max(case Subject when '語文' then grade else 0 end) as 語文,
max(case Subject when '數(shù)學(xué)' then grade else 0 end) as 數(shù)學(xué),
max(case Subject when '英語' then grade else 0 end) as 英語
from dbo.Tb_Student group by sname order by sname desc

declare @sql varchar(8000)
set @sql = 'select sname as ' + '姓名'
select @sql = @sql + ' , max(case Subject when ''' + Subject + ''' then grade else 0 end) [' + Subject + ']'
from (select distinct Subject from Tb_Student) as a
set @sql = @sql + ' from Tb_Student group by sname order by sname desc'
exec(@sql)

select t.sname AS 姓名,
sum(decode(t.subject,'語文',grade,null))語文 ,
sum(decode(t.subject,'數(shù)學(xué)',grade,null)) 數(shù)學(xué),
sum(decode(t.subject,'英語',grade,null)) 英語
from Tb_Student t group by sname order by sname desc

select *
from (select sname,[Course ] ='數(shù)學(xué)',[Score]=[數(shù)學(xué)] from Tb_students union all
select sname,[Course]='英語',[Score]=[英語] from Tb_students union all
select sname,[Course]='語文',[Score]=[語文] from Tb_students)t
order by sname,case [Course] when '語文' then 1 when '數(shù)學(xué)' then 2 when '英語' then 3 end
go
 --列轉(zhuǎn)行的靜態(tài)方案：UNPIVOT,sql2005及以后版本
 
 SELECT sname,Subject, grade
 from dbo.Tb_students
 unpivot(grade for Subject in([語文],[數(shù)學(xué)],[英語]))as up
 GO
 
 
 --列轉(zhuǎn)行的動(dòng)態(tài)方案：UNPIVOT,sql2005及以后版本
 --因?yàn)樾惺莿?dòng)態(tài)所以這里就從INFORMATION_SCHEMA.COLUMNS視圖中獲取列來構(gòu)造行，同樣也使用了XML處理。
 declare @s nvarchar(4000)
select @s=isnull(@s+',','')+quotename(Name)
from syscolumns where ID=object_id('Tb_students') and Name not in('sname')
order by Colid
exec('select sname,[Subject],[grade] from Tb_students unpivot ([grade] for [Subject] in('+@s+'))b')

go
select
  sname,[Subject],[grade]
from
  Tb_students
unpivot
  ([grade] for [Subject] in([數(shù)學(xué)],[英語],[語文]))b