>>>sorted(a, key=lambdax:x['age'])# 按年齡排序 [{'name':'A','age':30}, {'name':'C','age':40}, {'name':'B','age':50}] 再舉一個數(shù)組元素求平方的例子,這次用map函數(shù): >>> a = [1,2,3] >>> for item in map(lambda x:x*x, a): print(item, end=', ') 輸出: ...
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