#切片法
def reverse1():
 s=input("請輸入需要反轉的內(nèi)容：")
 return s[::-1]
reverse1()

#運行結果
In [23]: def reverse1():
 ...: s=input("請輸入需要反轉的內(nèi)容：")
 ...: return s[::-1]
 ...: 
 ...: reverse1()

請輸入需要反轉的內(nèi)容：你是一個小南瓜
Out[23]: '瓜南小個一是你'

#!/usr/bin/python
import sys
#打開文件進行寫入
myfile=open('test.txt','w') 
while 1:
 print "input your string \n"
 #readline會讀入最后的換行符
 line=sys.stdin.readline()
 #判斷輸入是否為空字符串
 if line.strip('\n')=='':
  break
 #原輸入字符串合并上反轉的字符串
 allmessage=line[:-1]+line.strip('\n')[::-1]
 print allmessage
 #輸入及轉換后的字符串寫入到文件中
 myfile.write(allmessage+'\n')
#記得關閉文件操作流
myfile.close()

#! /bin/sh
while true
do
  echo "Pls enter your string" "\n"
  read my
  if [ -z $my ];
  then
   break
  fi
  remy=$(echo $my | rev)
  echo $my$remy
  echo $my$remy >> test.txt
done

#遞歸反轉
def reverse2(s):
 if s=="":
 return s
 else:
 return reverse2(s[1:])+s[0]
reverse2("sidfmawsmdisd是當面問")

#運行結果
In [24]: def reverse2(s):
 ...: if s=="":
 ...: return s
 ...: else:
 ...: return reverse2(s[1:])+s[0]
 ...: 
 ...: reverse2("sidfmawsmdisd是當面問")
Out[24]: '問面當是dsidmswamfdis'

In [25]: l=['a', 'b', 'c', 'd']
 ...: l.reverse()
 ...: print (l)
['d', 'c', 'b', 'a']

#借用列表，使用reverse()方法
def reverse3(s):
 l=list(s)
 l.reverse()
 print("".join(l))
reverse3("soifmi34pomOsprey，，是")

#運行結果
In [26]: def reverse3(s):
 ...: l=list(s)
 ...: l.reverse()
 ...: print("".join(l))
 ...: 
 ...: reverse3("soifmi34pomOsprey，，是")
 ...: 
是，，yerpsOmop43imfios

s = 'abcde' 
s[::-1]

# -*- coding: utf-8 -*- 
 
#eclipse pydev, python 3.3 
#by C.L.Wang 
#time: 2014. 4. 11 
 
string = 'abcdef' 
 
def string_reverse1(string): 
 return string[::-1] 
 
def string_reverse2(string): 
 t = list(string) 
 l = len(t) 
 for i,j in zip(range(l-1, 0, -1), range(l//2)): 
 t[i], t[j] = t[j], t[i] 
 return "".join(t) 
 
def string_reverse3(string): 
 if len(string) <= 1: 
 return string 
 return string_reverse3(string[1:]) + string[0] 
 
from collections import deque 
def string_reverse4(string): 
 d = deque() 
 d.extendleft(string) 
 return ''.join(d) 
 
def string_reverse5(string): 
 #return ''.join(string[len(string) - i] for i in range(1, len(string)+1)) 
 return ''.join(string[i] for i in range(len(string)-1, -1, -1)) 
 
print(string_reverse1(string)) 
print(string_reverse2(string)) 
print(string_reverse3(string)) 
print(string_reverse4(string)) 
print(string_reverse5(string)) 

def reverse(str):
 alist = list(str)
 alist.reverse()
 new_str = ''.join(alist)
 return new_str
print reverse('jb51.net')