#coding:utf8
#! /usr/bin/env python
# 注釋說明：shape表示一個俄羅斯方塊形狀 cell表示一個小方塊
import sys
from random import choice
import pygame
from pygame.locals import *
from block import O, I, S, Z, L, J, T

COLS = 16
ROWS = 20
CELLS = COLS * ROWS
CELLPX = 32 # 每個cell的像素寬度
POS_FIRST_APPEAR = COLS / 2
SCREEN_SIZE = (COLS * CELLPX, ROWS * CELLPX)
COLOR_BG = (0, 0, 0)


def draw(grid, pos=None):
 # grid是一個list，要么值為None，要么值為'Block'
 # 非空值在eval（）的作用下，用于配置顏色
 if pos: # 6x5
  s = pos - 3 - 2 * COLS # upper left position
  for p in range(0, COLS):
   q = s + p * COLS
   for i in range(q, q + 6):
    if 0 <= i < CELLS:
     # 0 <=i < CELLS:表示i這個cell在board內部。
     c = eval(grid[i] + ".color") if grid[i] else COLOR_BG
     # 執(zhí)行著色。shape的cell涂對應的class設定好的顏色，否則涂黑（背景色）
     a = i % COLS * CELLPX
     b = i / COLS * CELLPX
     screen.fill(c, (a, b, CELLPX, CELLPX))
 else: # all
  screen.fill(COLOR_BG)
  for i, occupied in enumerate(grid):
   if occupied:
    c = eval(grid[i] + ".color") # 獲取方塊對應的顏色
    a = i % COLS * CELLPX # 橫向長度
    b = i / COLS * CELLPX # 縱向長度
    screen.fill(c, (a, b, CELLPX, CELLPX))
    # fill:為cell上色, 第二個參數(shù)表示rect
 pygame.display.flip()
 # 刷新屏幕


def phi(grid1, grid2, pos): # 4x4
# 兩個grid之4*4區(qū)域內是否會相撞（沖突）
 s = pos - 2 - 1 * COLS # upper left position
 for p in range(0, 4):
  q = s + p * COLS
  for i in range(q, q + 4):
   try:
    if grid1[i] and grid2[i]:
     return False
   except:
    pass
 return True


def merge(grid1, grid2):
 # 合并兩個grid
 grid = grid1[:]
 for i, c in enumerate(grid2):
  if c:
   grid[i] = c
 return grid


def complete(grid):
 # 減去滿行
 n = 0
 for i in range(0, CELLS, COLS):
  # 步長為一行。
  if not None in grid[i:i + COLS]:
  #這一句很容易理解錯誤。
  #實際含義是：如果grid[i:i + COLS]都不是None,那么執(zhí)行下面的語句
   grid = [None] * COLS + grid[:i] + grid[i + COLS:]
   n += 1
 return grid, n
#n表示減去的行數(shù)，用作統(tǒng)計分數(shù)

pygame.init()
pygame.event.set_blocked(None)
pygame.event.set_allowed((KEYDOWN, QUIT))
pygame.key.set_repeat(75, 0)
pygame.display.set_caption('Tetris')
screen = pygame.display.set_mode(SCREEN_SIZE)
pygame.display.update()

grid = [None] * CELLS
speed = 500
screen.fill(COLOR_BG)
while True: # spawn a block
 block = choice([O, I, S, Z, L, J, T])()
 pos = POS_FIRST_APPEAR
 if not phi(grid, block.grid(pos), pos): break # you lose
 pygame.time.set_timer(KEYDOWN, speed)
 # repeatedly create an event on the event queue
 # speed是時間間隔。。。speed越小，方塊下落的速度越快。。。speed應該換為其他名字

 while True: # move the block
  draw(merge(grid, block.grid(pos)), pos)
  event = pygame.event.wait()
  if event.type == QUIT: sys.exit()
  try:
   aim = {
    K_UNKNOWN: pos+COLS,
    K_UP: pos,
    K_DOWN: pos+COLS,
    K_LEFT: pos-1,
    K_RIGHT: pos+1,
   }[event.key]
  except KeyError:
   continue
  if event.key == K_UP:
   # 變形
   block.rotate()

  elif event.key in (K_LEFT, K_RIGHT) and pos / COLS != aim / COLS:
   # pos/COLS表示當前位置所在行
   # aim/COLS表示目標位置所在行
   # 此判斷表示，當shape在左邊界時，不允許再向左移動（越界。。）,在最右邊時向右也禁止
   continue

  grid_aim = block.grid(aim)
  if grid_aim and phi(grid, grid_aim, aim):
   pos = aim
  else:
   if event.key == K_UP:
    block.rotate(times=3)
   elif not event.key in (K_LEFT, K_RIGHT):
    break

 grid = merge(grid, block.grid(pos))
 grid, n = complete(grid)
 if n:
  draw(grid)
  speed -= 5 * n
  if speed < 75: speed = 75

#coding:utf-8
#! /usr/bin/env python
COLS = 16
ROWS = 20

class Block():
 color = (255,255,255)
 def __init__(self):
  self._state = 0
 def __str__(self):
  return self.__class__.__name__
 def _orientations(self):
  raise NotImplementedError()
 def rotate(self, times=1):
  for i in range(times):
   if len(self._orientations())-1 == self._state:
    self._state = 0
    #只要_state比_orientations長度-1還要小，就讓_state加1

   else:
    self._state += 1
 def blades(self):
  # 返回對應形狀的一種旋轉形狀。(返回一個list,list中每個元素是一個(x,y))
  return self._orientations()[self._state]

 def grid(self, pos, cols=COLS, rows=ROWS):
  # grid()函數(shù)：對于一個形狀，從它的cell中的pos位置，按照orientations的位置提示，把所有cell涂色
  # pos表示的是shape中的一個cell，也就是(0,0)
  if cols*rows <= pos:
   return None
  # 這種情況應該不可能出現(xiàn)吧。如果出現(xiàn)<=的情況
  # 那么，pos都跑到界外了。。

  grid = [None] * cols * rows
  grid[pos] = str(self)
  for b in self.blades():
   x, y = b
   # pos/cols表示pos處于board的第幾行
   if pos/cols != (pos+x)/cols:
    return None
   i = pos + x + y * cols
   if i < 0:
    continue
   elif cols*rows <= i:
    return None
   grid[i] = str(self)
   # 給相應的其他位置都“涂色”,比如對于方塊，是O型的，那么pos肯定是有值的，pos位于有上角。。
  return grid

# 以下每個形狀class，_orientations（）都返回形狀的列表。(0,0)一定被包含在其中，為了省略空間所以都沒有寫出.
class O(Block):
 color = (207,247,0)
 def _orientations(self):
  return (
   [(-1,0), (-1,1), (0,1)],
   )
class I(Block):
 color = (135,240,60)
 def _orientations(self):
  return (
   [(-2,0), (-1,0), (1,0)],
   [(0,-1), (0,1), (0,2)],
   )
class S(Block):
 color = (171,252,113)
 def _orientations(self):
  return (
   [(1,0), (-1,1), (0,1)],
   [(0,-1), (1,0), (1,1)],
   )
class Z(Block):
 color = (243,61,110)
 def _orientations(self):
  return (
   [(-1,0), (0,1), (1,1)],
   [(1,-1), (1,0), (0,1)],
   )
class L(Block):
 color = (253,205,217)
 def _orientations(self):
  return (
   [(-1,1), (-1,0), (1,0)],
   [(0,-1), (0,1), (1,1)],
   [(-1,0), (1,0), (1,-1)],
   [(-1,-1), (0,-1), (0,1)],
   )
class J(Block):
 color = (140,180,225)
 def _orientations(self):
  return (
   [(-1,0), (1,0), (1,1)],
   [(0,1), (0,-1), (1,-1)],
   [(-1,-1), (-1,0), (1,0)],
   [(-1,1), (0,1), (0,-1)],
   )
class T(Block):
 color = (229,251,113)
 def _orientations(self):
  return (
   [(-1,0), (0,1), (1,0)],
   [(0,-1), (0,1), (1,0)],
   [(-1,0), (0,-1), (1,0)],
   [(-1,0), (0,-1), (0,1)],
   )