import re 
temp = "司法局讓我和戶 1 5. 8 0. ?。?？？ 客戶維護戶外" 
temp = temp.decode("utf8") 
string = re.sub("[\s+\.\!\/_,$%^*(+\"\']+|[+——！，。？、~@#￥%……&*（）]+".decode("utf8"), "".decode("utf8"),temp) 
print string 

'''引入string模塊'''
import string
'''使用標點符號常量'''
string.punctuation
text = "*/@》--【】--12()測試*()"

'''去除字符串中所有的字符，可增加自定義字符'''
def strclear(text,newsign=''):
  import string # 引入string模塊
  signtext = string.punctuation + newsign # 引入英文符號常量，可附加自定義字符，默認為空
  signrepl = '@'*len(signtext) # 引入符號列表長度的替換字符
  signtable = str.maketrans(signtext,signrepl) # 生成替換字符表
  return text.translate(signtable).replace('@','') # 最后將替換字符替換為空即可

strclear(text,'》【】')

static str.maketrans(x[, y[, z]])
This static method returns a translation table usable for str.translate().

If there is only one argument, 
it must be a dictionary mapping Unicode ordinals (integers) or characters (strings of length 1) to Unicode ordinals, 
strings (of arbitrary lengths) or None. Character keys will then be converted to ordinals.

If there are two arguments, 
they must be strings of equal length, 
and in the resulting dictionary, 
each character in x will be mapped to the character at the same position in y. 
If there is a third argument, it must be a string, whose characters will be mapped to None in the result.

import string

i = 'Hello, how are you!'

i.translate(str.maketrans('', '', string.punctuation))
>>>'Hello how are you'

　i = 'hello world i am li'
　i.translate(str.maketrans('','','l'))

>>>'heo word i am i'