python使用正則篩選信用卡
本文實(shí)例為大家分享了python使用正則篩選信用卡的具體代碼,供大家參考,具體內(nèi)容如下
本文來(lái)源于兩個(gè)簡(jiǎn)單的題目:
1.判斷一對(duì)單詞是否是" Anagrams "
2.判斷信用卡是否合理
判斷 Anagramsstrong>
anagrams 的百度翻譯:由顛倒字母順序而構(gòu)成的字(短語(yǔ))
而題目給出例子:
[ DOG , ODG ]
[ DOG , DOG ]
[ DOG , GOD ]
[ DOG , GDO ]
均為 anagrams 。
那思路就簡(jiǎn)單了,直接拆分字母,排序,比較就 ok 。
判斷信用卡
題目給出的要求如下:
The criteria are:
• It must start with a 4,5 or 6
• It must be exactly 16 digits
• It must be numbers only
• It can have a digits in groups of 4, separated by one hyphen “-“
• It should not contain any other characters.
• It must NOT have any 4 repeated digits.
樣例輸出如下:
378282246310005 Invalid
30569309025904 Invalid
6011111111111117 Invalid
5123-2332-3232-3213 valid
py文件
兩個(gè)題目合并在一個(gè) py 文件中?!?br /> 而入?yún)?shù)分別是兩個(gè)文件的名字,一個(gè)是 anagram.txt ,另一個(gè)是 credit_cards.txt ,他們分別長(zhǎng)這樣:


最后的程序長(zhǎng)這樣:
#! /usr/bin/python3
import re
###############################
##You need to implet the following methods:
##
##Question 1
##anagram_validator()
##
##Question 2
##credit_card_validator()
################################
###################################################
# Question 1: Check for anagrams:#
###################################################
def get_list(src_str):
sub_list=[]
word_tmp=''
for word in src_str:
if word != ',':
word_tmp = word_tmp+word
else:
sub_list.append(word_tmp)
word_tmp = ''
return sub_list
def read_anagram(file_name):
'''
Input: a file name
Return: a nested list of two words list
Example : [[word1,word2],[word3,word4]...etc]
'''
with open(file_name,encoding = 'utf-8') as f:
return_list =[]
file_conment = f.read()
file_conment_new = re.sub(r'\n',',',file_conment)
file_conment_new = file_conment_new+','
subs_list = get_list(file_conment_new)
i=0
while i < (len(subs_list)-1):
return_list.append([subs_list[i],subs_list[i+1]])
i=i+2
return return_list
def anagram_validator(anagram):
'''
Input is the output from "read_anagram()".
Return: list of "anagrams" or "Not anagrams" values for each two words
example input (dog,gdo),(try,elm) then output would be ["anagrams","Not anagrams"] with sequence of the input
'''
result_list=[]
for i in range(len(anagram)):
word_font = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][0])))
word_back = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][1])))
if word_font == word_back:
result_list.append('Anagrams')
else:
result_list.append('Not anagrams')
return result_list
############################################
# Question 2: Validate credit cards #
############################################
def read_credit_cards(file_name):
'''
Input: a file name
Return tuple of numbers
'''
with open(file_name,encoding='utf-8') as f:
card_conment = f.read()
card_conment = re.sub(r'\[','',card_conment)
card_conment = re.sub(r'\]','',card_conment)
card_conment = card_conment+','
card_list = get_list(card_conment)
return tuple(card_list)
def credit_card_validator(numbers):
'''
Input: tuple of numbers
Return:dictionary of credit card numbers where key is the number and value if valid or invalid
'''
validator_list=[]
credit_dict={}
for i in range(len(numbers)):
validator_list.append(numbers[i])
for i in range(len(numbers)):
ch_num = 0
repeat_flag = 0
for ch in validator_list[i]:
if ord("A")<=ord(ch)<=ord("Z"):
ch_num+=1
break
tmp_list = []
tmp_list = (re.sub(r"[^\d]", "", validator_list[i]))
for index in range(len(tmp_list)-4):
if(tmp_list[index] == tmp_list[index+1] and
tmp_list[index] == tmp_list[index+2] and
tmp_list[index] == tmp_list[index+3] ):
repeat_flag = 1
break;
if(validator_list[i][0] != '4' and
validator_list[i][0] != '5' and
validator_list[i][0] != '6' ):
credit_dict[validator_list[i]]='Invalid'
elif( len(re.sub(r"\D", "", validator_list[i])) != 16 ):
credit_dict[validator_list[i]]='Invalid'
elif(ch_num > 0):
credit_dict[validator_list[i]]='Invalid'
elif(
(re.search(r"-",validator_list[i])) and
( validator_list[i][4] != '-' or
validator_list[i][9] != '-'or
validator_list[i][14] != '-'
)
):
credit_dict[validator_list[i]]='Invalid'
elif(re.search(r"[^-\d]",validator_list[i])):
credit_dict[validator_list[i]]='Invalid'
elif(repeat_flag == 1 ):
credit_dict[validator_list[i]]='Invalid'
else :
credit_dict[validator_list[i]]='Valid'
space_str = ''
return credit_dict
def print_credit_card_summary(dict_o):
'''
Input: dict
Return:
printing summary of validation result - space between credit card and status is 40 width
example:
378282246310005 Invalid
30569309025904 Invalid
'''
space_str = ''
for key in dict_o:
new_str = key + dict_o[key]
if(dict_o[key] == "Valid"):
new_str_tmp = new_str[:-5]
space_lenth = 46-len(new_str)
for x in range(space_lenth):
space_str +=' '
print(new_str_tmp + space_str + 'Valid')
space_str=''
else :
new_str_tmp = new_str[:-7]
space_lenth = 48-len(new_str)
for x in range(space_lenth):
space_str +=' '
print(new_str_tmp + space_str + 'Invalid')
space_str=''
####### THE CODE BELOW IS FOR TESTING###################
############### DO NOT CHANGE #########################
import sys
if __name__ == '__main__':
# Take care of the console inputs
if len(sys.argv) <= 1:
sys.argv = ['', "anagram.txt", "credit_cards.txt"]
stars = '*' * 40
print(stars)
print("Testing Question 1 --- Anagrams?")
print(stars)
# testing reading_anagrams
try:
anagram = read_anagram(sys.argv[1])
if not anagram:
print("read_anagram() returns None.")
else:
print("anagram: ", anagram)
print()
except Exception as e:
print("Error (readnumbers()): ", e)
# testing anagram_validator
Anagrams = 0
NAnagrams = 0
try:
if not anagram: # Question 1 has not been implemented
print("anagram_validator() skipped....")
else:
result = anagram_validator(anagram)
if result == None:
print("anagram_validator() returns None.")
else:
for i in result:
if i == "Anagrams":
Anagrams += 1
elif i == "Not anagrams":
NAnagrams += 1
print("Number of valid Anagrams is {} and Not anagrams is {}.".format(Anagrams, NAnagrams))
except Exception as e:
print("Error (anagram_validator()):", e)
# testing Question 2
print("\n\n" + stars)
print("Testing Question 2 --- Credit Card Validator")
print(stars)
# Testing reading_credit_cards
try:
tup = read_credit_cards(sys.argv[2])
if not tup:
print("read_credit_cards() returns None.")
else:
print("The tuple of credit_cards: {}".format(tup))
except Exception as e:
print("Error (read_credit_cards()):", e)
# Testing credit_card_validator
vcc = 0
ivcc = 0
try:
if not tup: # Readin_Question 2 has not been implemented
print("credit_card_validator() skipped...")
else:
cc_dict = credit_card_validator(tup)
tmp_cc_dict = cc_dict
if not cc_dict:
print("credit_card_validator() returns None.")
else:
for items in cc_dict.keys():
if cc_dict[items] == "Valid":
vcc += 1
elif cc_dict[items] == "Invalid":
ivcc += 1
print("Number of valid credit cards is {} and invalid {}.".format(vcc, ivcc))
except Exception as e:
print("Error (credit_card_validator()):", e)
# testing Question 2
print("\n\n" + stars)
print("Testing Question 2b --- Print Credit Card Summary")
print(stars)
# Testing print_credit_card_summary
try:
if not tmp_cc_dict: # Dict credit card output has not been implemented
print("print_credit_card_summary() skipped...")
else:
import io # do not delete this line
from contextlib import redirect_stdout # do not delete this line
f = io.StringIO()
with redirect_stdout(f):
print_credit_card_summary(tmp_cc_dict)
out = f.getvalue()
if not out:
print("print_credit_card_summary() returns None.")
else:
count44 = 0
count46 = 0
for line in out.splitlines():
if len(line) - len(line.split()) == 44:
count44 += 1
elif len(line) - len(line.split()) == 46:
count46 += 1
if count44 == vcc and count46 == ivcc:
print("Your format looks good")
else:
print("You might have some issues in your summary format")
except Exception as e:
print("Error (print_credit_card_summary()):", e)
以上就是本文的全部?jī)?nèi)容,希望對(duì)大家的學(xué)習(xí)有所幫助,也希望大家多多支持腳本之家。
相關(guān)文章
PyCharm 解決找不到新打開項(xiàng)目的窗口問題
這篇文章主要介紹了PyCharm 解決找不到新打開項(xiàng)目的窗口問題,具有很好的參考價(jià)值,希望對(duì)大家有所幫助。一起跟隨小編過來(lái)看看吧2021-01-01
Python實(shí)踐之使用Pandas進(jìn)行數(shù)據(jù)分析
在數(shù)據(jù)分析領(lǐng)域,Python的Pandas庫(kù)是一個(gè)非常強(qiáng)大的工具。這篇文章將為大家詳細(xì)介紹如何使用Pandas進(jìn)行數(shù)據(jù)分析,希望對(duì)大家有所幫助2023-04-04
Django使用 Bootstrap 樣式修改書籍列表過程解析
這篇文章主要介紹了Django使用 Bootstrap 樣式修改書籍列表過程解析,文中通過示例代碼介紹的非常詳細(xì),對(duì)大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價(jià)值,需要的朋友可以參考下2019-08-08
python列表推導(dǎo)式入門學(xué)習(xí)解析
這篇文章主要介紹了python列表推導(dǎo)式入門學(xué)習(xí)解析,文中通過示例代碼介紹的非常詳細(xì),對(duì)大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價(jià)值,需要的朋友可以參考下2019-12-12
利用Python pandas對(duì)Excel進(jìn)行合并的方法示例
這篇文章主要給大家介紹了關(guān)于利用Python pandas對(duì)Excel進(jìn)行合并的方法示例,文中通過示例代碼介紹的非常詳細(xì),對(duì)大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價(jià)值,需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)學(xué)習(xí)吧2020-11-11
python GUI庫(kù)圖形界面開發(fā)之PyQt5動(dòng)態(tài)(可拖動(dòng)控件大小)布局控件QSplitter詳細(xì)使用方法與實(shí)例
這篇文章主要介紹了python GUI庫(kù)圖形界面開發(fā)之PyQt5動(dòng)態(tài)(可拖動(dòng)控件大小)布局控件QSplitter詳細(xì)使用方法與實(shí)例,需要的朋友可以參考下2020-03-03

