import itertools as its
import string

def createDict(path,repeats,words):
	dict = its.product(words,repeat=repeats) 
	'''這里的words是要迭代的字符串，repeats是生成的密碼長(zhǎng)度，生成的dict是一個(gè)返回元組的迭代器'''
	f = open(path,'a')
	for cipher in dict:
		f.write(''.join(cipher) + '\n')
	f.close()

def main():
	numbers = string.digits #包含0-9的字符串
	path = '輸入你的字典路徑'
	length = 你要迭代的密碼長(zhǎng)度
	for i in range(1,length):
		createDict(path,i,numbers)

if __name__=="__main__":
	main()

from threading import Thread
from unrar import rarfile
import os

'''首先我們要讀取字典，字典可能太大因此我們采用迭代器'''

def get_pwd(dict_path):
	with open(dict_path,'r') as f:
		for pwd in f:
			yield pwd.strip()

def decode_rar(fp,pwd,extract_path):
	try:
		fp.extractall(extract_path,pwd=pwd) 
	except:
		pass
	else:
		print('the pwd is>',pwd)
'''
事實(shí)上我在嘗試時(shí)似乎從來(lái)沒(méi)有到達(dá)過(guò)else，這樣可能是得不到解壓密碼的。我的
一種得到密碼的想法如下，但是運(yùn)行效率可能會(huì)降低


def decode_rar(fp,pwd,check_file,extract_path):
	fp.extractall(extract_path,pwd=pwd)
	if os.path.exists(check_file):
		print('The pwd is:',pwd)
		exit(0)
其中check_file可以設(shè)置為fp.namelist()[0]
并且該方法不能使用多線(xiàn)程，因此速度會(huì)降低很多
'''

def main():
	extract_path = '你要解壓的路徑'
	dict_path = '你的字典路徑'
	filename = '你的rar路徑'
	fp = rarfile.RarFile(filename)
	pwds = get_pwd(dict)
	'''使用多線(xiàn)程可提高速度'''
	for pwd in pwds:
		t = Thread(target=rar_file,args=(fp,pwd,extract_path))
		t.start()

import tkinter as tk
import os
from tkinter import messagebox
from unrar import rarfile
from threading import Thread

def getPwd(dict):
  with open(dict,'r') as f:
    for pwd in f:
      yield pwd.strip()
def slowerDecode(fp,pwd,check_file,extract_path):
  fp.extractall(extract_path,pwd=pwd)
  if os.path.exists(check_file):
    messagebox.showinfo(message="密碼："+pwd)
    messagebox.showinfo(message="程序結(jié)束")
    messagebox.showinfo(message="密碼："+pwd)
    exit(0)
	
def quickDecode(fp,pwd,extract_path):
  fp.extractall(extract_path,pwd=pwd)


def check(obs):
  flag = 1
  for ob in obs:
    if not ob.checkExist():
      flag = 0
      ob.showError()  

  if(not flag):
    return 0
  else:
    for ob in obs:
      if not ob.check():
        flag = 0
        ob.showError()
		
  if (not flag):
    return 0
  else:
    for ob in obs:
      ob.right()
    return 1
		
def main(obs):
  extract_path = obs[0].path_input.get()
  rar_path = obs[1].path_input.get()
  txt_path = obs[2].path_input.get()
  pwds = getPwd(txt_path)
  global var1
  global var2
  if(check(obs)):
    if(var1.get() == 0 and var2.get() == 0):
      messagebox.showerror(message="選擇一個(gè)選項(xiàng)！?。?)
    elif(var1.get() == 0 and var2.get() == 1):
      fp = rarfile.RarFile(rar_path)
      check_file = fp.namelist()[0]
      for pwd in pwds:
        slowerDecode(fp,pwd,check_file,extract_path)
    elif(var1.get() == 1 and var2.get() == 0):
      fp = rarfile.RarFile(rar_path)
      for pwd in pwds:
        t = Thread(target=quickDecode,args=(fp,pwd,extract_path))
        t.start()
      exit(0)
    else:
      messagebox.showerror(message="只選擇一個(gè)?。。?)
    

class FolderPath:
  
  def __init__(self,y=0,error_message="Not exists!",path_input="",text=''):
    self.y = y
    self.error_message = error_message
    self.path_input = path_input
    self.text = text
	
  def createLabel(self):
    label = tk.Label(window,bg="white",font=("楷體",13),width=20,text=self.text)
    cv.create_window(100,self.y,window=label)
  
  def createEntry(self):
  	entry = tk.Entry(window,fg="blue",width="40",bg="#ffe1ff",textvariable=self.path_input)
  	cv.create_window(330,self.y,window=entry)
  
  def show(self):
    self.createLabel()
    self.createEntry()
	
  def showError(self,color="red"):
    label = tk.Label(window,bg="white",fg=color,font=("楷體",13),width="10",text=self.error_message)
    cv.create_window(530,self.y,window=label)
  
  def checkExist(self):
    self.error_message = 'Not exists!'
    if not os.path.exists(self.path_input.get()):
      return 0
    return 1
  
  def check(self):
    if not os.path.isdir(self.path_input.get()):
      self.error_message = 'Not a dir!'
      return 0
    else:
      return 1
  
  def right(self):
    self.error_message = "right path!"
    self.showError('#00FFFF')
	
  
class FilePath(FolderPath):
  def check(self):
    if (self.path_input.get().split('.')[-1] == self.suffix):
      return 1
    else:
      self.error_message = "Not "+self.suffix + '!'
      return 0
  

window = tk.Tk()
window.title('made by qiufeng')
window.geometry('600x300')
cv = tk.Canvas(window,width=600,height=300,bg='white')
cv.pack()

folderpath = FolderPath(y=140,path_input=tk.StringVar(),text="請(qǐng)輸入解壓路徑")
folderpath.show()


rarpath = FilePath(y=60,path_input=tk.StringVar(),text="請(qǐng)輸入rar路徑")
rarpath.suffix = 'rar'
rarpath.show()

txtpath = FilePath(y=100,path_input=tk.StringVar(),text="請(qǐng)輸入字典路徑")
txtpath.suffix = 'txt'
txtpath.show()
obs = [folderpath,rarpath,txtpath]

#多選框
var1 = tk.IntVar()
var2 = tk.IntVar()
ck1 = tk.Checkbutton(window,text="直接破解(無(wú)法獲得密碼)",variable=var1)
cv.create_window(150,200,window=ck1)
ck2 = tk.Checkbutton(window,text="慢速(可獲得密碼)",variable=var2)
cv.create_window(132,230,window=ck2)
button = tk.Button(window,text="確認(rèn)",command=lambda: main(obs))
cv.create_window(90,260,window=button)

window.mainloop()