##一個(gè)簡(jiǎn)單的2折交叉驗(yàn)證
from sklearn.model_selection import KFold
import numpy as np
X=np.array([[1,2],[3,4],[1,3],[3,5]])
Y=np.array([1,2,3,4])
KF=KFold(n_splits=2) #建立4折交叉驗(yàn)證方法 查一下KFold函數(shù)的參數(shù)
for train_index,test_index in KF.split(X):
  print("TRAIN:",train_index,"TEST:",test_index)
  X_train,X_test=X[train_index],X[test_index]
  Y_train,Y_test=Y[train_index],Y[test_index]
  print(X_train,X_test)
  print(Y_train,Y_test)
#小結(jié)：KFold這個(gè)包 劃分k折交叉驗(yàn)證的時(shí)候，是以TEST集的順序?yàn)橹鞯模e例來說，如果劃分4折交叉驗(yàn)證，那么TEST選取的順序?yàn)閇0].[1],[2],[3]。

#提升
import numpy as np
from sklearn.model_selection import KFold
#Sample=np.random.rand(50,15) #建立一個(gè)50行12列的隨機(jī)數(shù)組
Sam=np.array(np.random.randn(1000)) #1000個(gè)隨機(jī)數(shù)
New_sam=KFold(n_splits=5)
for train_index,test_index in New_sam.split(Sam): #對(duì)Sam數(shù)據(jù)建立5折交叉驗(yàn)證的劃分
#for test_index,train_index in New_sam.split(Sam): #默認(rèn)第一個(gè)參數(shù)是訓(xùn)練集，第二個(gè)參數(shù)是測(cè)試集
  #print(train_index,test_index)
  Sam_train,Sam_test=Sam[train_index],Sam[test_index]
  print('訓(xùn)練集數(shù)量:',Sam_train.shape,'測(cè)試集數(shù)量:',Sam_test.shape) #結(jié)果表明每次劃分的數(shù)量


#Stratified k-fold 按照百分比劃分?jǐn)?shù)據(jù)
from sklearn.model_selection import StratifiedKFold
import numpy as np
m=np.array([[1,2],[3,5],[2,4],[5,7],[3,4],[2,7]])
n=np.array([0,0,0,1,1,1])
skf=StratifiedKFold(n_splits=3)
for train_index,test_index in skf.split(m,n):
  print("train",train_index,"test",test_index)
  x_train,x_test=m[train_index],m[test_index]
#Stratified k-fold 按照百分比劃分?jǐn)?shù)據(jù)
from sklearn.model_selection import StratifiedKFold
import numpy as np
y1=np.array(range(10))
y2=np.array(range(20,30))
y3=np.array(np.random.randn(10))
m=np.append(y1,y2) #生成1000個(gè)隨機(jī)數(shù)
m1=np.append(m,y3)
n=[i//10 for i in range(30)] #生成25個(gè)重復(fù)數(shù)據(jù)

skf=StratifiedKFold(n_splits=5)
for train_index,test_index in skf.split(m1,n):
  print("train",train_index,"test",test_index)
  x_train,x_test=m1[train_index],m1[test_index]