200行python代碼實(shí)現(xiàn)2048游戲

更新時(shí)間：2019年07月17日 14:31:44 作者：PastoralDog

這篇文章主要為大家詳細(xì)介紹了200行Python代碼實(shí)現(xiàn)2048游戲，具有一定的參考價(jià)值，感興趣的小伙伴們可以參考一下

Python實(shí)戰(zhàn)系列用于記錄實(shí)戰(zhàn)項(xiàng)目中的思路，代碼實(shí)現(xiàn)，出現(xiàn)的問題與解決方案以及可行的改進(jìn)方向

本文為第2篇–200行Python代碼實(shí)現(xiàn)2048

一、分析與函數(shù)設(shè)計(jì)

1.1 游戲玩法

2048這款游戲的玩法很簡(jiǎn)單，每次可以選擇上下左右滑動(dòng)，每滑動(dòng)一次，所有的數(shù)字方塊都會(huì)往滑動(dòng)的方向靠攏，系統(tǒng)也會(huì)在空白的地方亂數(shù)出現(xiàn)一個(gè)數(shù)字方塊，相同數(shù)字的方塊在靠攏、相撞時(shí)會(huì)相加。（介紹來自百度百科）

1.2 函數(shù)設(shè)計(jì)

_init _() 初始化4*4游戲地圖，分?jǐn)?shù)等游戲基本數(shù)據(jù)
is_gameover() 判斷是否結(jié)束游戲
rannumber() 玩家每次移動(dòng)時(shí)在地圖上隨機(jī)生成2、4
show() 在控制臺(tái)打印出4*4游戲地圖
print_score() 在控制臺(tái)打印出當(dāng)前分?jǐn)?shù)
up(), upmove() 上移
down(), downmove() 下移
left(), leftmove() 左移
right(), rightmove() 右移
nextstep() 讀取玩家按鍵

二、代碼實(shí)現(xiàn)

注：IDE為Spyder，Python版本為3.6

# -*- coding: utf-8 -*-
"""
Created on Sat Sep 29 16:29:04 2018

@author: PastoralDog
"""
import random

class game2048(object):
  def __init__(self):
    self.score=0
    self.number=[[0,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]]
    self.move=0
    seed=random.randint(0,15)
    line=int(seed/4)
    row=seed%4
    self.number[line][row]=2    
  
  def is_gameover(self):
    numbersum=0
    for i in range(4):
      for j in range(4):
        if (self.number[i][j]!=0):
          numbersum+=1
    if(numbersum!=16): return False
    for i in range(4):
      for j in range(3):
        if(self.number[i][j+1]==self.number[i][j]): return False
    for i in range(3):
      for j in range(4):
        if(self.number[i+1][j]==self.number[i][j]): return False
    print("游戲結(jié)束")
    print("您的得分為："+str(self.score))
    self.__init__()
    return True
  
  def rannumber(self):
    rannumber=random.randint(1,10)   
    if(rannumber<=8): rannumber=2
    else: rannumber=4
    done=0
    count=0
    for i in range(4):
      for j in range(4):
        if(self.number[i][j]==0):
          count+=1
    while(done==0 and count!=0):
      ranplace=random.randint(0,15)
      line=int(ranplace/4)
      row=ranplace%4
      if(self.number[line][row]==0):
        done=1
        self.number[line][row]=rannumber      
    
  def show(self):
    print(self.number[0])
    print(self.number[1])
    print(self.number[2])
    print(self.number[3])
    
  def print_score(self):
    print("得分："+str(self.score))
    
  def upmove(self):
    for i in range(1,4):
      for j in range(4):
        temp=i
        while(temp>=1 and self.number[temp-1][j]==0):
          box=self.number[temp-1][j]
          self.number[temp-1][j]=self.number[temp][j]
          self.number[temp][j]=box
          if(self.number[temp][j]!=0):self.move=1
          temp-=1
  
  def up(self):
    self.upmove()
    for i in range(1,4):
      for j in range(4):
        if(self.number[i-1][j]==self.number[i][j]):
          if(self.number[i-1][j]!=2048):
            self.score+=self.number[i][j]
            self.number[i][j]=0
            self.number[i-1][j]=2*self.number[i-1][j]         
    self.upmove()      
    if(self.move!=0):self.rannumber()
    self.move=0
    self.show()
    self.is_gameover()
    self.print_score()
  
  def downmove(self):
     for i in range(2,-1,-1):
       for j in range(4):
        temp=i
        while(temp<=2 and self.number[temp+1][j]==0 ):
          box=self.number[temp+1][j]
          self.number[temp+1][j]=self.number[temp][j]
          self.number[temp][j]=box
          if(self.number[temp+1][j]!=0):self.move=1
          temp+=1
      
  def down(self):
    self.downmove()
    for i in range(2,-1,-1):
      for j in range(4):
        if(self.number[i+1][j]==self.number[i][j]):
          if(self.number[i+1][j]!=2048):
            self.score+=self.number[i][j]
            self.number[i][j]=0
            self.number[i+1][j]=2*self.number[i+1][j] 
    self.downmove()
    if(self.move!=0):self.rannumber()
    self.move=0
    self.show()
    self.is_gameover()
    self.print_score()
  
  def leftmove(self):
    for i in range(4):
      for j in range(1,4):    
        temp=j
        while(temp>=1 and self.number[i][temp-1]==0 ):
          box=self.number[i][temp-1]
          self.number[i][temp-1]=self.number[i][temp]
          self.number[i][temp]=box
          if(self.number[i][temp-1]!=0):self.move=1
          temp-=1
  
  def left(self):
    self.leftmove()
    for i in range(4):
      for j in range(0,3):
        if(self.number[i][j+1]==self.number[i][j]):
          if(self.number[i][j+1]!=2048):
            self.score+=self.number[i][j]
            self.number[i][j+1]=0
            self.number[i][j]=2*self.number[i][j] 
    self.leftmove()
    if(self.move!=0):self.rannumber()
    self.move=0
    self.show()
    self.is_gameover()
    self.print_score()
  
  def rightmove(self):
    for i in range(4):
      for j in range(2,-1,-1):    
        temp=j
        while(temp<=2 and self.number[i][temp+1]==0 ):
          box=self.number[i][temp+1]
          self.number[i][temp+1]=self.number[i][temp]
          self.number[i][temp]=box
          self.move=1
          temp+=1
  
  def right(self):
    self.rightmove()
    for i in range(4):
      for j in range(2,-1,-1):
        if(self.number[i][j+1]==self.number[i][j]):
          if(self.number[i][j+1]!=2048):
            self.score+=self.number[i][j]
            self.number[i][j]=0
            self.number[i][j+1]=2*self.number[i][j+1] 
    self.rightmove()
    if(self.move!=0):self.rannumber()
    self.move=0
    self.show()
    self.is_gameover()
    self.print_score()
  
  def nextstep(self,step):
    if(step=='w'): self.up()
    elif(step=='s'): self.down()
    elif(step=='a'): self.left()  
    elif(step=='d'): self.right()
    else: pass
       
if __name__ == '__main__':
  game=game2048()
  game.show()
  while(True):
    step=input()
    if(step=='b'):break
    game.nextstep(step)

三、問題與解決方案

1.地圖的儲(chǔ)存與表示：目前沒有界面設(shè)計(jì)，因此就用二維數(shù)組直接儲(chǔ)存與表示

2.數(shù)組越界：調(diào)試代碼中遇到過五六次，除了牢記要邊緣檢測(cè)外， and 語句左右條件順序也要有講究。

例：while(temp<=2 and self.number[temp+1][j]==0 ) 注：self.number為4*4的二維數(shù)組
當(dāng)temp=3時(shí)，語句在temp<=2 被阻塞，不會(huì)執(zhí)行self.number[temp+1][j]==0，此時(shí)沒有問題;
若語句改為while(self.number[temp+1][j]==0 and temp<=2), 先執(zhí)行self.number[temp+1][j]==0，此時(shí)編譯器報(bào)錯(cuò)數(shù)組越界

四、可行的改進(jìn)方向

1.添加可視化界面，可考慮Tkinter，QT等

2.拓展游戲地圖大小為N x N

本人水平有限，歡迎大家提出問題與建議。

以上就是本文的全部?jī)?nèi)容，希望對(duì)大家的學(xué)習(xí)有所幫助，也希望大家多多支持腳本之家。

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