#并發(fā)運行,效率高,但競爭同一打印終端,帶來了打印錯亂
from multiprocessing import Process
import time
def task(name):
  print("%s 1" % name)
  time.sleep(1)
  print("%s 2" % name)
  time.sleep(1)
  print("%s 3" % name)
if __name__ == '__main__':
  for i in range(3):
    p = Process(target=task, args=("子進(jìn)程%s" % i,))
    p.start()
'''
子進(jìn)程2 1
子進(jìn)程0 1
子進(jìn)程1 1
子進(jìn)程2 2
子進(jìn)程1 2
子進(jìn)程0 2
子進(jìn)程2 3
子進(jìn)程1 3
子進(jìn)程0 3
'''

from multiprocessing import Process, Lock
import time
def task(name, mutex):
  # 加鎖
  mutex.acquire()
  print("%s 1" % name)
  time.sleep(1)
  print("%s 2" % name)
  time.sleep(1)
  print("%s 3" % name)
  # 把鎖拆了
  mutex.release()
if __name__ == '__main__':
  # 建一個對象實例
  mutex = Lock()
  for i in range(3):
    # 把鎖傳給子進(jìn)程 讓所有子進(jìn)程用同一把鎖
    p = Process(target=task, args=("子進(jìn)程%s" % i, mutex))
    p.start()
'''
現(xiàn)在程序啟動 所有進(jìn)程首先會去搶鎖 只有搶到鎖的才能運行
等這個進(jìn)程運行完了解鎖后 再到其他進(jìn)程繼續(xù)搶鎖
'''
'''
子進(jìn)程0 1
子進(jìn)程0 2
子進(jìn)程0 3
子進(jìn)程1 1
子進(jìn)程1 2
子進(jìn)程1 3
子進(jìn)程2 1
子進(jìn)程2 2
子進(jìn)程2 3
'''