import re
 
lt = []
d = {}
for i in range(3):
 a = input('請(qǐng)輸入第%d個(gè)三元式'%(i + 1))
 st = a.split("=")
 r = re.compile('(-?\d?)[xyz]')
 b = re.findall(r, st[0])
 print(b)
 for j in range(3):
  if b[j] == "":
   b[j] = 1
  if b[j] == '-':
   b[j] = -1
 d = {
  'x': int(b[0]),
  'y': int(b[1]),
  'z': int(b[2]),
  'sum':int(st[1])
 }
 lt.append(d)
print(lt)
t = lt[0]['x'] / lt[1]['x']
for i in lt[0]:
 lt[1][i] = lt[1][i] * t - lt[0][i]
 
t1 = lt[0]['x'] / lt[2]['x']
for i in lt[0]:
 lt[2][i] = lt[2][i] * t1 - lt[0][i]
 
t2 = lt[1]['y'] / lt[2]['y']
 
for i in lt[0]:
 lt[2][i] = lt[2][i] * t2 - lt[1][i]
 
 
z = lt[2]['sum'] / lt[2]['z']
y = (lt[1]['sum'] - lt[1]['z'] * z) / lt[1]['y']
x = (lt[0]['sum'] - lt[0]['z'] * z - lt[0]['y'] * y)/lt[0]['x']
 
print(x,y,z)
#樣例輸入
#請(qǐng)輸入第1個(gè)三元式3x+6y-5z=12
#請(qǐng)輸入第2個(gè)三元式x-3y+2z=-2#請(qǐng)輸入第3個(gè)三元式5x-y+4z=10

def x_3():
 t = [42,43,44] 
 d = 0
 for z in t:
  print("當(dāng)剩余%d元時(shí)："%(44-z))
  for i in range(z//3+1):
   for n in range(z//5+1):
    for m in range(z//7+1):
     for p in range (z//11+1):
      if 3*i + 5*n +7*m +11*p == z:
       d += 1
       print("第%d個(gè)解為:(%d,%d,%d,%d)"%(d,i+1,n+1,m+1,p+1) )

##先每本書買一本，這樣就保障了每本書最低一本的要求，這樣還剩余44元，可隨意分配
##按照只買種本書、兩種書、三種書、四種書的邏輯思路編寫代碼
def x_1(): ##只買一種書
 for m in [3,5,7,11]:
  x = 1
  while True:
   if 42 <= m*x <=44: ##大于等于42，是因?yàn)樽疃嗍Ｓ?元
    print("只買%d的元的書，購(gòu)買%d本，剩余%d元" %(m,x+1,44-m*x))
    break
   elif m*x >44:
    print("不存在只買%d元的書的情況"%m)
    break
   else:
    x +=1

def x_2(): ##只買兩種書
 ls = [3,5,7,11]
 m = 0
 ix = 0
 for m in range(3):
  ix = 0
  while True:
   if ix*ls[m] <= 44-ls[m+1]:
    ix += 1
    for q in range(m+1,4):
     iy = 1
     while True:
      if 42 <= ls[m]*ix +ls[q]*iy <=44:
       print("購(gòu)買%d元書%d本，購(gòu)買%d元書%d本，剩余%d元"%(ls[m],ix+1,ls[q],iy+1,44-(ls[m]*ix +ls[q]*iy)))
       iy += 1
      elif ls[m]*ix +ls[q]*iy > 44:
       iy = 0
       break
      else:
       iy += 1
   else:
    break