#快樂(lè)的數(shù)字
def getSumofSquares(num):
    numStr=str(num) #將待計(jì)算的數(shù)字轉(zhuǎn)換成字符串類型
    sum=0
    digitls=[int(x) for x in numStr] #從字符串中提取出每一位數(shù)字存入一個(gè)列表
    #注：該步略顯多余，因?yàn)閜ython中字符串可以和列表一樣切片取值或循環(huán)，見(jiàn)下方更新部分
    #print(digitls)
    for i in digitls:
        sum += i**2
    return sum

def main():
    n = input() #輸入一個(gè)正整數(shù)
    sumofSqrs = eval(n)
    count = 0
    while sumofSqrs != 1:
        sumofSqrs = getSumofSquares(sumofSqrs)
        count += 1
        if count > 2000: #當(dāng)計(jì)算次數(shù)超過(guò)2000次時(shí)，跳出循環(huán)結(jié)束計(jì)算
            print("False")
            break
    else:
        print("True")

main()

#（新）快樂(lè)的數(shù)字
def getSumofSquares(num):
    numStr=str(num)
    sum=0
    for i in numStr:
        sum += int(i)**2
    return sum

def main():
    n = input() #n為一個(gè)正整數(shù)
    sumofSqrs = eval(n)
    while sumofSqrs != 1 and sumofSqrs != 4: #或 while sumofSqrs not in [1,4,16,37,58,89,145,42,20]
        sumofSqrs = getSumofSquares(sumofSqrs)
    else:
        if sumofSqrs == 1:
            print("True")
        else:
            print("False")

main()

def happy(n):
        try:
                if n==1:
                        print('True')
                else:
                        new = str(n)
                        sum = 0
                        for c in new:
                                sum += int(c)**2
                        return happy(sum)
        except Exception as e:
                print('False')
                # print(e)

n = eval(input())
happy(n)

        d = {}
        while True:
            m = 0
            while n > 0:
                m += (n%10)**2
                n //= 10 
            if m in d:
                return False
            if m == 1:
                return True
            d[m] = m
            n = m

class Solution(object):
    def isHappy(self, n):
        """
        :type n: int
        :rtype: bool
        """
        record = []
        sq_sum = 0
        se_n = n

        while se_n != 1:
            sq_sum = 0
            while se_n > 0:
                sq_sum += (se_n % 10) * (se_n % 10)
                se_n = se_n / 10
            if sq_sum in record:
                return False
            record.append(sq_sum)
            se_n = sq_sum

        return True