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一篇文章帶你了解Python和Java的正則表達(dá)式對(duì)比

更新時(shí)間：2021年09月14日 15:14:16 作者：8su

正則表達(dá)式有元字符及不同組合來構(gòu)成，通過巧妙的構(gòu)造正則表達(dá)式可以匹配任意字符串，并完成復(fù)雜的字符串處理任務(wù)，希望本片文章能給你帶來幫助

簡單批量替換

舉例：將and 批量替換為&&

Python實(shí)現(xiàn)

import re
def transformSimple(fromRegex, toText, inText):
    return re.sub(fromRegex, toText,inText, flags =re.I)
if __name__ == "__main__":
    inText = "x =1 and y =2"
    fromRegex = " and "
    toText = " && "
    outText = transformSimple(fromRegex,toText,inText )
    print(outText)
	## OUTPUT： x =1 && y =2

Java實(shí)現(xiàn)

import java.util.*;
import java.util.regex.*;
public class RegexTest {
	private static String transformSimple(String regexPattern, String replText, String inText){
        return Pattern.compile(regexPattern, Pattern.CASE_INSENSITIVE).matcher(inText).replaceAll(replText);
    }
    public static void main(String[] args) {
	    String input = "x =1 and y =2";
        String patternString =" and ";
        String toText = " && ";
        String outText ="";
        outText = transformSimple(patternString, toText, input);
        System.out.println("RESULT: " + outText);
}

// RESULT: x =1 && y =2

復(fù)雜模板替換

舉例：將x in (1,2)批量替換為[1,2].contains(x)

分析：模板化

輸入分組捕獲 (\S+)\s+in\s*\((.+?)\)
輸出分組填寫 [@2].contains(@1) – @1和@2分別對(duì)應(yīng)分組捕獲中的第1組和2組。

Python實(shí)現(xiàn)

import re
def transformComplex(fromRegex, toText, inText):
    regObj = re.compile(fromRegex, flags =re.I)
    for match in regObj.finditer(inText):
        index = 1
        outText = toText
        for group in match.groups():
            outText = outText.replace("@"+str(index), group)
            index +=1
        inText = inText.replace(match.group(0), outText)
    return inText
if __name__ == "__main__":
    fromRegex = "(\S+)\s+in\s*\((.+?)\)"
    toText = "[@2].contains(@1)"
    inText = "x in (1,2) and y in (3,4)"
    outText22 = transformComplex(fromRegex, toText, inText)
    print(outText22)
    ## OUTPUT: [1,2].contains(x) and [3,4].contains(y)

Java實(shí)現(xiàn)

import java.util.*;
import java.util.regex.*;
public class RegexTest {
	private static String transformComplex(String regexPattern, String replText, String inText){
        Pattern pattern = Pattern.compile(regexPattern, Pattern.CASE_INSENSITIVE);
        Matcher matcher = pattern.matcher(inText);
        String outText ="";
        while (matcher.find()){
            outText =  replText;
            for (int i =1; i <= matcher.groupCount(); i++){
                outText = outText.replace("@"+i, matcher.group(i));
            }
            inText = inText.replace(matcher.group(0), outText);
        }
        return inText;
    }
    public static void main(String[] args) {
        String input = "x in (1,2) and y in (3,4)";
        String patternString ="(\\S+)\\s+in\\s*\\((.+?)\\)";
        String toText = "[@2].contains(@1)";
        String outText ="";
        outText = transformComplex(patternString, toText, input);
        System.out.println("RESULT: " + outText);
    }
}
// RESULT: [1,2].contains(x) and [3,4].contains(y)