# int 強(qiáng)制把數(shù)據(jù)變成整型
"""int float bool 純數(shù)字字符串"""
var1 = 13
var2 = 5.67
var3  = True
var4 = "123456"
var5 = "123abc"
var6 = 3+5j
res = int(var2)
res = int(var3) # True  => 1
res = int(False)# False => 0
res = int(var4)
# res = int(var5) error
# res = int(var6) error
print(res , type(res))
# float 強(qiáng)制把數(shù)據(jù)變成小數(shù)
"""int float bool 純數(shù)字字符串"""
res = float(var1)
res = float(var3) # True  => 1.0
res = float(False)# False => 0.0
res = float(var4) # 123456.0 
print(res , type(res))
# complex 強(qiáng)制把數(shù)據(jù)變成復(fù)數(shù)
"""int float bool 純數(shù)字字符串 complex"""
res = complex(var1) # 添加0j 表達(dá)復(fù)數(shù)
res = complex(var2)
res = complex(var3)  # True => 1+0j
res = complex(False) # False => 0j
res = complex(var4)  # 123456+0j
print(res , type(res))
# bool 強(qiáng)制把數(shù)據(jù)變成布爾型 (布爾型為假的十中情況)
"""布爾型可以強(qiáng)轉(zhuǎn)一切數(shù)據(jù)類型"""
""" 0 , 0.0 , False , 0j '' [] () set() {} None """
res = bool(None)
print(res , type(res))
# 初始化變量時(shí),不清楚用什么值,無(wú)腦寫上None
"""None 代表空的,代表什么也沒有,一般用于初始化變量"""
a =None
b =None

"""
默認(rèn)轉(zhuǎn)換成當(dāng)前數(shù)據(jù)類型的一個(gè)值
int() float() complex() bool()
"""
res = bool() 
print(res , type(res))

# 額外的擴(kuò)展
"""
strvar = "123"
strvar = "3.134"
strvar = "5+3j"
# res = int(strvar)
# print(res,type(res))
# res = float(strvar)
# print(res,type(res))
# res = complex(strvar)
# print(    res,type(res)    )
"""

低精度默認(rèn)向高精度進(jìn)行轉(zhuǎn)換
bool -> int -> float -> complex
"""
# bool + int
res = True + 100
print(res ,type(res)) # 1 + 100 => 101
# bool + float
res = True  + 344.565 # 1.0 + 344.565 => 345.565
print(res ,type(res)) 
# bool + complex
res = True + 7 - 90j  #  1 + 0j + 7 - 90j => 8 - 90j
print(res ,type(res)) 
# int + float
res = 5 + 7.88 # 5.0 + 7.88 => 12.88
print(res ,type(res)) 
# int + complex
res = 5 + 6 + 8j # 5 + 0j   6 + 8j => 11 + 8j
print(res ,type(res)) 
# float + complex 
res = 5.66 + 9.1 -90j # 5.66 + 0j + 9.1 -90j => 14.76-90j
print(res ,type(res)) 
'''
# 小數(shù)的精度損耗 (小數(shù)后面一般有時(shí)截取15~18位,但是不完全,存在精度損耗)
"""不要用小數(shù)作比較,咬不準(zhǔn)"""
print(0.1 + 0.2 == 0.3)
print(5.1 + 5.9 == 11.0)
0.0999999999999999
'''

var1 = "我愛你,文哥哥"
var2 = [1,2,3]
var3 = (4,4,5)
var4 = {"陳璐","上朝氣","劉子濤","合理"}
var5 = {"cl":"文質(zhì)彬彬,斯文敗類","szq":"學(xué)霸","lzt":"籃球少年","hl":"武大高手"}
var6 = 90
var7 = True

# str 強(qiáng)制轉(zhuǎn)換成字符串
"""所有的數(shù)據(jù)類型都可以轉(zhuǎn)換, 在當(dāng)前的數(shù)據(jù)類型兩邊套上引號(hào)"""
res = str(var2) 
res = str(var3)
res = str(var4)
res = str(var5)
res = str(var6)
res = str(var7)
print(res ,type(res))
# repr 不轉(zhuǎn)移字符原型化輸出字符串
print(repr(res))
# list 強(qiáng)制轉(zhuǎn)換成列表
"""
如果是字符串:把字符串中的每個(gè)元素單獨(dú)拿出來(lái),作為列表中的新元素
如果是字典:  只保留字典中的鍵
如果是其他容器數(shù)據(jù):就是單純的在原數(shù)據(jù)類型德兩邊換上[]括號(hào)
"""
res = list(var1)
res = list(var3)
res = list(var4)
# 字典: 只獲取字典得鍵,忽略掉值
res = list(var5)
# res = list(var6) error 只能是容器間的互轉(zhuǎn)
print(res ,type(res))
# tuple 強(qiáng)制轉(zhuǎn)換成元組
"""
如果是字符串:把字符串中的每個(gè)元素單獨(dú)拿出來(lái),作為元組中的新元素
如果是字典:  只保留字典中的鍵
如果是其他容器數(shù)據(jù):就是單純的在原數(shù)據(jù)類型得兩邊換上()括號(hào)
"""
res = tuple(var1)
res = tuple(var2)
res = tuple(var4)
res = tuple(var5)
print(res ,type(res))
# set 強(qiáng)制轉(zhuǎn)換成集合
"""
如果是字符串:把字符串中的每個(gè)元素單獨(dú)拿出來(lái),作為集合中的新元素
如果是字典:  只保留字典中的鍵
如果是其他容器數(shù)據(jù):就是單純的在原數(shù)據(jù)類型得兩邊換上{}括號(hào)
"""
res = set(var1)
res = set(var2)
res = set(var5)
print(res ,type(res))

# 多濾掉列表中所有重復(fù)元素;
lst = [1,222,3,3,3,44,88,999,77,88,1]
res = set(lst)
print(res)
# 在把當(dāng)前的集合轉(zhuǎn)換成原來(lái)的列表
res2 = list(res)
print(res2)

"""
默認(rèn)不加任何值,轉(zhuǎn)換成該數(shù)據(jù)類型的空值
str() list()  tuple()  set()  dict()
"""
res = dict()
print(res )
print(type(res))

# 二級(jí)列表
lst = [1,2,3,[4,5,6]]
# 二級(jí)元組
tup = (1,2,(10,11))
# 二級(jí)集合
setvar = {1,2,("a","b")}
# 二級(jí)字典
dic = {"a":1,"b":{"c":10}}
print(dic["b"]["c"])
# 四級(jí)容器
container = [1,2,3,(4,5,6,{"a":1,"b":[11,"bingo"]})]
# (4,5,6,{"a":1,"b":[11,"bingo"]})
res1 = container[-1]
print(res1)
# {'a': 1, 'b': [11, 'bingo']}
res2 = res1[-1]
print(res2)
# [11, 'bingo']
res3 = res2["b"]
print(res3)
# bingo
res4 = res3[-1]
print(res4)
# 一步簡(jiǎn)寫
res = container[-1][-1]["b"][-1]
print(res)
# 等長(zhǎng)的二級(jí)容器
"""外面是容器,里面的元素也是容器,且元素個(gè)數(shù)相同"""
lst = [(1,2,3),[4,5,6],{7,8,9}]

"""
要求: 必須是等長(zhǎng)的二級(jí)容器,并且里面的元素個(gè)數(shù)是2個(gè);
外層是列表,元組,集合 , 里層是列表或者元組的等長(zhǎng)二級(jí)容器 => 字典;
"""
# 1.外層是列表,里層是列表或者元組
lst = [ ["a",1] , ("b",2) ]
dic = dict(lst)
print(dic , type(dic)) # {'a': 1, 'b': 2} <class 'dict'>
# 2.外層是元組,里層是列表或者元組
tup = ( ["a",1] , ("b",2) )
dic = dict(lst)
print(dic , type(dic))
# 3.外層是集合,里層是元組
setvar = { ("a",1) , ("b",2) }
dic = dict(setvar)
print(dic , type(dic))
# 例外1:外層是列表/元組,里層放集合
"""可以實(shí)現(xiàn),不推薦使用,因?yàn)檫_(dá)不到想要的目的,集合無(wú)序,不推薦使用"""
lst = [ ["a",1] , {"b","250"} ]
dic = dict(lst)
print(dic)
# 例外2:外層是列表/元組,里層放字符串
""" 字符串長(zhǎng)度只能是2位,有極大的局限性,不推薦使用"""
lst = ["a1","b2"]
# lst = ["a11","b22"] error 
# dic = dict(lst)
# print(dic)

外層是集合，里面不能是列表
lst = [ ["a",1] , {"b","250"}]
dic = dict(lst)
print(dic)    這里可能會(huì)輸出{'a':1,'b':'250'}或者{'a':1,'250':'b'}
lst = ["a1","b2"]
dic = dict(lst)
print(dic) 這里會(huì)輸出{a:1,b:2}
lst = ["a11","b22"]
dic = dict(lst)
print(dic)  這里就會(huì)報(bào)錯(cuò)
isinstance比type用的多

"""
# 使用方法一
isinstance(數(shù)據(jù),類型)  
如果該數(shù)據(jù)是這個(gè)類型,返回True 反之,返回False
類型: int float complex bool str list tuple set dict
# 使用方法二
isinstance(  數(shù)據(jù), (類型1,類型2,類型3...)   )
如果該數(shù)據(jù)在所對(duì)應(yīng)的類型元組當(dāng)中,返回True,反之,返回False
"""
# 使用方法一
n = 123
res = isinstance(n , int)
print(res)
n = [1,2,3]
res = isinstance(n , list)
res = isinstance(n , tuple)
print(res)
# 使用方法二
n = "1233"
res = isinstance(n , (list , tuple ,set , str)  )
print(res)

n = {"a":1}
res = isinstance(n , (list , tuple ,set , str)  )
print(res)

1.int,float,complex,bool 分別可以強(qiáng)轉(zhuǎn)哪些數(shù)據(jù)
2.強(qiáng)轉(zhuǎn)布爾類型為假的值有哪些?
3.強(qiáng)轉(zhuǎn)字典的條件
4.bingo如何獲取
[1,2,3,4,[5,6,7,[8,9,10,(11,{"a":{"bb":98},"pp":{"d":'bingo'}})]]] 
5. 哪個(gè)不能轉(zhuǎn)換成字典,為什么?
    (1){('a',1),{'b',2}}
    (2){('a',1),('b',2)}
    (3){('a',1),"c3"}
    (4){('a',1),"b88"}

在一個(gè)文件中-5 - 正無(wú)窮
a = 3
b = 3   
a和b的id是一樣
a = b =3 不管是不是-5到正無(wú)窮，a和b的id都是一樣的