這篇文章主要為大家介紹了利用Pygame模塊實(shí)現(xiàn)的檢測(cè)按鍵正確的小游戲：每個(gè)字母有10秒的按鍵時(shí)間，如果按對(duì)，則隨機(jī)產(chǎn)生新的字符，一共60s,如果時(shí)間到了，則游戲結(jié)束?？靵?lái)跟隨小編一起學(xué)習(xí)一下吧

游戲功能

游戲開(kāi)始，屏幕隨機(jī)顯示一個(gè)字符，按 Enter 游戲開(kāi)始，每個(gè)字母有10秒的按鍵時(shí)間，如果按對(duì)，則隨機(jī)產(chǎn)生新的字符，一共60s,如果時(shí)間到了，則游戲結(jié)束。

引入包，初始化配置信息

import sys, random, time, pygame
from pygame.locals import *

pygame.init()
screen = pygame.display.set_mode((600, 500))
pygame.display.set_caption("打字速度")

while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()

    screen.fill((255, 192, 128))

    pygame.display.update()

初始化游戲提示信息

首先設(shè)置兩種字體，然后封裝一個(gè)屏幕上寫(xiě)字的函數(shù)，寫(xiě)出提示。

white = 255, 255, 255

font1 = pygame.font.SysFont("方正粗黑宋簡(jiǎn)體", 24)
font2 = pygame.font.SysFont("方正粗黑宋簡(jiǎn)體", 200)

def print_text(font, x, y, text, color=white):
    img_text = font.render(text, True, color)
    screen.blit(img_text, (x, y))
while True:
	---
	print_text(font1, 0, 0, "看看你的速度有多快")
	print_text(font1, 0, 30, "請(qǐng)?jiān)?0秒內(nèi)嘗試")
	---

顯示隨機(jī)的字母

使用 ASCII 字符表，鍵盤(pán)上默認(rèn)輸入的是小寫(xiě)，97 - 122，然后我們使用chr() 函數(shù)減去32，就可以得到對(duì)應(yīng)的大寫(xiě)字母，將其寫(xiě)在窗口上

# 隨機(jī)的字母
correct_answer = random.randint(97, 122)
while True:
	---
	print_text(font2, 0, 240, chr(correct_answer - 32), (255, 255, 0))
	---

設(shè)置游戲的屬性

# 是否按鍵
key_flag = False
# 游戲是否開(kāi)始 默認(rèn)是結(jié)束的
game_over = True
# 隨機(jī)的字母
correct_answer = random.randint(97, 122)
# 分?jǐn)?shù)
score = 0
# 開(kāi)始時(shí)間
clock_start = 0
# 讀秒倒計(jì)時(shí)
seconds = 11

根據(jù)用戶的按鍵改變對(duì)應(yīng)的屬性，如果游戲重新開(kāi)始，重置對(duì)應(yīng)的屬性。

while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            key_flag = True
        elif event.type == KEYUP:
            key_flag = False
    keys = pygame.key.get_pressed()
    if keys[K_ESCAPE]:
        sys.exit()
    if keys[K_RETURN]:
        if game_over:
            game_over = False
            score = 0
            clock_start = time.perf_counter()
            seconds = 11

使用 time.perf_counter() 獲取程序運(yùn)行到當(dāng)前的時(shí)間，計(jì)算差值，實(shí)現(xiàn)在屏幕上的倒計(jì)時(shí),并根據(jù)時(shí)間結(jié)束游戲或者重新開(kāi)始

	current = time.perf_counter() - clock_start

    if seconds - current < 0:
        game_over = True
    elif current <= 10:
        if keys[correct_answer]:
            correct_answer = random.randint(97, 122)
            score += 1
            clock_start = time.perf_counter()
    if not game_over:
        print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))
        print_text(font1, 500, 40,  str(int(time.perf_counter())))

完整代碼?

import sys, random, time, pygame
from pygame.locals import *

pygame.init()
screen = pygame.display.set_mode((600, 500))
pygame.display.set_caption("打字速度")
font1 = pygame.font.SysFont("方正粗黑宋簡(jiǎn)體", 24)
font2 = pygame.font.SysFont("方正粗黑宋簡(jiǎn)體", 200)
white = 255, 255, 255
yellow = 255, 255, 0
# 是否按鍵
key_flag = False
# 游戲是否開(kāi)始 默認(rèn)是結(jié)束的
game_over = True
# 隨機(jī)的字母
correct_answer = random.randint(97, 122)
# 分?jǐn)?shù)
score = 0
# 開(kāi)始時(shí)間
clock_start = 0
# 讀秒倒計(jì)時(shí)
seconds = 11


def print_text(font, x, y, text, color=white):
    img_text = font.render(text, True, color)
    screen.blit(img_text, (x, y))


while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            key_flag = True
        elif event.type == KEYUP:
            key_flag = False
    keys = pygame.key.get_pressed()
    if keys[K_ESCAPE]:
        sys.exit()
    if keys[K_RETURN]:
        if game_over:
            game_over = False
            score = 0
            clock_start = time.perf_counter()
            seconds = 11

    screen.fill((0, 100, 0))
    current = time.perf_counter() - clock_start
    print_text(font1, 0, 0, "看看你的速度有多快")
    print_text(font1, 0, 30, "請(qǐng)?jiān)?0秒內(nèi)嘗試")

    if seconds - current < 0:
        game_over = True
    elif current <= 10:
        if keys[correct_answer]:
            correct_answer = random.randint(97, 122)
            score += 1
            clock_start = time.perf_counter()
    # 如果按鍵了
    if key_flag:
        print_text(font1, 500, 0, "按鍵了")

    if not game_over:
        print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))
        print_text(font1, 500, 40,  str(int(time.perf_counter())))

    print_text(font1, 0, 100, "分?jǐn)?shù): " + str(score))

    if game_over:
        print_text(font1, 0, 160, "請(qǐng)按enter開(kāi)始游戲...")

    print_text(font2, 0, 240, chr(correct_answer - 32), yellow)

    pygame.display.update()

以上就是Pygame實(shí)戰(zhàn)之檢測(cè)按鍵正確的小游戲的詳細(xì)內(nèi)容，更多關(guān)于Pygame按鍵正確游戲的資料請(qǐng)關(guān)注腳本之家其它相關(guān)文章！

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