import sys, random, time, pygame
from pygame.locals import *

pygame.init()
screen = pygame.display.set_mode((600, 500))
pygame.display.set_caption("打字速度")

while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()

    screen.fill((255, 192, 128))

    pygame.display.update()

初始化游戲提示信息

首先設置兩種字體，然后封裝一個屏幕上寫字的函數(shù)，寫出提示。

white = 255, 255, 255

font1 = pygame.font.SysFont("方正粗黑宋簡體", 24)
font2 = pygame.font.SysFont("方正粗黑宋簡體", 200)

def print_text(font, x, y, text, color=white):
    img_text = font.render(text, True, color)
    screen.blit(img_text, (x, y))
while True:
	---
	print_text(font1, 0, 0, "看看你的速度有多快")
	print_text(font1, 0, 30, "請在10秒內嘗試")
	---

顯示隨機的字母

使用 ASCII 字符表，鍵盤上默認輸入的是小寫，97 - 122，然后我們使用chr() 函數(shù)減去32，就可以得到對應的大寫字母，將其寫在窗口上

# 隨機的字母
correct_answer = random.randint(97, 122)
while True:
	---
	print_text(font2, 0, 240, chr(correct_answer - 32), (255, 255, 0))
	---

設置游戲的屬性

# 是否按鍵
key_flag = False
# 游戲是否開始 默認是結束的
game_over = True
# 隨機的字母
correct_answer = random.randint(97, 122)
# 分數(shù)
score = 0
# 開始時間
clock_start = 0
# 讀秒倒計時
seconds = 11

根據(jù)用戶的按鍵改變對應的屬性，如果游戲重新開始，重置對應的屬性。

while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            key_flag = True
        elif event.type == KEYUP:
            key_flag = False
    keys = pygame.key.get_pressed()
    if keys[K_ESCAPE]:
        sys.exit()
    if keys[K_RETURN]:
        if game_over:
            game_over = False
            score = 0
            clock_start = time.perf_counter()
            seconds = 11

使用 time.perf_counter() 獲取程序運行到當前的時間，計算差值，實現(xiàn)在屏幕上的倒計時,并根據(jù)時間結束游戲或者重新開始

	current = time.perf_counter() - clock_start

    if seconds - current < 0:
        game_over = True
    elif current <= 10:
        if keys[correct_answer]:
            correct_answer = random.randint(97, 122)
            score += 1
            clock_start = time.perf_counter()
    if not game_over:
        print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))
        print_text(font1, 500, 40,  str(int(time.perf_counter())))

完整代碼?

import sys, random, time, pygame
from pygame.locals import *

pygame.init()
screen = pygame.display.set_mode((600, 500))
pygame.display.set_caption("打字速度")
font1 = pygame.font.SysFont("方正粗黑宋簡體", 24)
font2 = pygame.font.SysFont("方正粗黑宋簡體", 200)
white = 255, 255, 255
yellow = 255, 255, 0
# 是否按鍵
key_flag = False
# 游戲是否開始 默認是結束的
game_over = True
# 隨機的字母
correct_answer = random.randint(97, 122)
# 分數(shù)
score = 0
# 開始時間
clock_start = 0
# 讀秒倒計時
seconds = 11


def print_text(font, x, y, text, color=white):
    img_text = font.render(text, True, color)
    screen.blit(img_text, (x, y))


while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == KEYDOWN:
            key_flag = True
        elif event.type == KEYUP:
            key_flag = False
    keys = pygame.key.get_pressed()
    if keys[K_ESCAPE]:
        sys.exit()
    if keys[K_RETURN]:
        if game_over:
            game_over = False
            score = 0
            clock_start = time.perf_counter()
            seconds = 11

    screen.fill((0, 100, 0))
    current = time.perf_counter() - clock_start
    print_text(font1, 0, 0, "看看你的速度有多快")
    print_text(font1, 0, 30, "請在10秒內嘗試")

    if seconds - current < 0:
        game_over = True
    elif current <= 10:
        if keys[correct_answer]:
            correct_answer = random.randint(97, 122)
            score += 1
            clock_start = time.perf_counter()
    # 如果按鍵了
    if key_flag:
        print_text(font1, 500, 0, "按鍵了")

    if not game_over:
        print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))
        print_text(font1, 500, 40,  str(int(time.perf_counter())))

    print_text(font1, 0, 100, "分數(shù): " + str(score))

    if game_over:
        print_text(font1, 0, 160, "請按enter開始游戲...")

    print_text(font2, 0, 240, chr(correct_answer - 32), yellow)

    pygame.display.update()

以上就是Pygame實戰(zhàn)之檢測按鍵正確的小游戲的詳細內容，更多關于Pygame按鍵正確游戲的資料請關注腳本之家其它相關文章！

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