《詐金花》又叫三張牌，是在全國(guó)廣泛流傳的一種民間多人紙牌游戲。比如JJ比賽中的詐金花(贏三張)，具有獨(dú)特的比牌規(guī)則。游戲過程中需要考驗(yàn)玩家的膽略和智慧。--《百度百科》前幾天在交流群里邊，有個(gè)叫【^-^】的粉絲分享了一道撲克牌詐金花的題目，要求用Python實(shí)現(xiàn)，題目如下：

自己寫一個(gè)程序，實(shí)現(xiàn)發(fā)牌、比大小判斷輸贏。

游戲規(guī)則：

一付撲克牌，去掉大小王，每個(gè)玩家發(fā)3張牌，最后比大小，看誰贏。

有以下幾種牌：

豹子：三張一樣的牌，如3張6.

順金：又稱同花順，即3張同樣花色的順子，如紅桃 5、6、7

順子：又稱拖拉機(jī)，花色不同，但是順子，如紅桃5、方片6、黑桃7，組成的順子

對(duì)子：2張牌一樣

單張：?jiǎn)螐堊畲蟮氖茿

這幾種牌的大小順序?yàn)椋?豹子>順金>順子>對(duì)子>單張

一、思路

針對(duì)這個(gè)問題，首先需要構(gòu)造一副撲克牌，根據(jù)撲克牌的屬性特征，進(jìn)行不斷的拆解，然后構(gòu)造玩家用戶，這里經(jīng)常會(huì)用到字典和列表來存儲(chǔ)信息，屢試不爽。

二、解決方案

針對(duì)該問題，粉絲【^-^】給出了解決方法，直接上代碼如下：

# -*- coding: utf-8 -*-
import random


puke = []  # 存儲(chǔ)撲克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '紅桃', '黑桃', '方塊']
sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
      '對(duì)子': 15, '順子': 30, '順金': 60, '豹子': 100}
count_new_list = []  # 存儲(chǔ)玩家分?jǐn)?shù)和排序后排名
count_dic = {}  # 存儲(chǔ)玩家分?jǐn)?shù)
# 準(zhǔn)備52張撲克
for hua in hua_list:
  for num in num_list:
    a = hua + num
    puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 隨機(jī)給五個(gè)玩家發(fā)牌
# print(len(puke))
for key, value in player_dic.items():
   for i in range(3):
        plate = random.sample(puke, 3)
        player_dic[key] = plate
        for i in plate:
            puke.remove(i)
print(player_dic)


# 獲取玩家的牌型
def paixing(list1):
  num = []
  huase = []
  for i in list1:
    a = i[2:]
    b = i[:2]
    num.append(a)
    huase.append(b)
  return num, huase

# sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4}
# 對(duì)數(shù)字的牌型進(jìn)行排序
def sort(num):
  new_num = []
  sort_list2 = []
  list1 = []
  for i in num:
    new_num.append(sort_dic[i])
  new_num = sorted(new_num)  # 排序后是[2, 4, 7]
  for new in new_num:
    sort_list2.append([k for k, v in sort_dic.items() if v == new])
  for m in sort_list2:
    for n in m:
      list1.append(n)
  return list1


# 對(duì)玩家的牌形統(tǒng)計(jì)分?jǐn)?shù)
def count(num, huase):
  a = 0
  base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
  if num[0] == num[1] and num[1] == num[2]:
    paixing = '豹子'
    a = base_count + sort_dic[paixing]

  elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
    1] and huase[1] == huase[2]):
    paixing = '順金'
    a = base_count + sort_dic[paixing]

  elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
      huase[0] != huase[
    1] or huase[1] != huase[2]):
    paixing = '順子'
    a = base_count + sort_dic[paixing]

  elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
      num[0] == num[2] and num[1] != num[0]):
    paixing = '對(duì)子'
    a = base_count + sort_dic[paixing]

  else:
    a = base_count
  return a


# 對(duì)存儲(chǔ)玩家分?jǐn)?shù)的字典進(jìn)行排序
def compare(count_dic):
  d = list(zip(count_dic.values(), count_dic.keys()))
  return sorted(d, reverse=True)


for key, value in player_dic.items():
  num, huase = paixing(value)
  num = sort(num)
  count1 = count(num, huase)
  count_dic[key] = count1
  print(key + "的牌為：" + str(value))
  count_new_list = compare(count_dic)
# print(count_new_list)
print('最終排名：' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
  1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")

代碼看上去確實(shí)挺多的，超過了100行，需要花點(diǎn)時(shí)間去讀，不過涉及的知識(shí)點(diǎn)并不復(fù)雜，基本上有點(diǎn)Python基礎(chǔ)，也可以理解。代碼運(yùn)行之后，可以看到效果如下：

不過后來我在讀取這份代碼的時(shí)候，發(fā)現(xiàn)中間有個(gè)地方寫的著實(shí)有些冗余，稍微修改下，代碼方面簡(jiǎn)潔一些，一些函數(shù)和變量命名加了一些對(duì)應(yīng)的現(xiàn)實(shí)意義的單詞，可讀性強(qiáng)了一丟丟，代碼如下：

# -*- coding: utf-8 -*-
import random


puke = []  # 存儲(chǔ)撲克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '紅桃', '黑桃', '方塊']
sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
      '對(duì)子': 15, '順子': 30, '順金': 60, '豹子': 100}
count_new_list = []  # 存儲(chǔ)玩家分?jǐn)?shù)和排序后排名
count_dic = {}  # 存儲(chǔ)玩家分?jǐn)?shù)
# 準(zhǔn)備52張撲克
for hua in hua_list:
  for num in num_list:
    a = hua + num
    puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 隨機(jī)給五個(gè)玩家發(fā)牌
print(len(puke))
for key, value in player_dic.items():
   for i in range(3):
        plate = random.sample(puke, 3)
        player_dic[key] = plate
        for i in plate:
            puke.remove(i)
print(player_dic)


# 獲取玩家的牌型
def paixing(list1):
  num = []
  huase = []
  for data in list1:
    huase_type = data[:2]
    pai_number = data[2:]
    num.append(pai_number)
    huase.append(huase_type)
  return num, huase


# 對(duì)玩家的牌形統(tǒng)計(jì)分?jǐn)?shù)
def get_score(num, huase):
  base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
  if num[0] == num[1] and num[1] == num[2]:
    paixing = '豹子'
    score = base_count + sort_dic[paixing]

  elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
    1] and huase[1] == huase[2]):
    paixing = '順金'
    score = base_count + sort_dic[paixing]

  elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
      huase[0] != huase[
    1] or huase[1] != huase[2]):
    paixing = '順子'
    score = base_count + sort_dic[paixing]

  elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
      num[0] == num[2] and num[1] != num[0]):
    paixing = '對(duì)子'
    score = base_count + sort_dic[paixing]

  else:
    score = base_count
  return score


if __name__ == '__main__':
  for key, value in player_dic.items():
    num, huase = paixing(value)
    # 對(duì)數(shù)字的牌型進(jìn)行排序
    num = sorted(num)
    score = get_score(num, huase)
    count_dic[key] = score
    print(key + "的牌為：" + str(value))
    # 對(duì)存儲(chǔ)玩家分?jǐn)?shù)的字典進(jìn)行排序
    count_new_list = sorted(zip(count_dic.values(), count_dic.keys()), reverse=True)
  print("最終排名：")
  for i in range(len(count_new_list)):
    print(count_new_list[i][1] + '\t', end='')