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利用Python實(shí)現(xiàn)簡(jiǎn)單的Excel統(tǒng)計(jì)函數(shù)

 更新時(shí)間：2022年07月21日 16:14:22   投稿：hqx  
這篇文章主要介紹了利用Python實(shí)現(xiàn)簡(jiǎn)單的Excel統(tǒng)計(jì)函數(shù)，文章圍繞主題展開(kāi)詳細(xì)的內(nèi)容介紹，具有一定的參考價(jià)值，需要的小伙伴可以參考一下

需求分析

根據(jù)原始數(shù)據(jù)，計(jì)算出累計(jì)和、回撤、連續(xù)正確、連續(xù)錯(cuò)誤、連續(xù)正確值與連續(xù)錯(cuò)誤值6項(xiàng)數(shù)據(jù)，其中原始數(shù)據(jù)大于等于0認(rèn)定為正確，原始數(shù)據(jù)小于0為錯(cuò)誤。明白了要求，那我們就開(kāi)始擼代碼吧~

解決步驟

import pandas as pd
#創(chuàng)建一個(gè)計(jì)算數(shù)據(jù)的函數(shù)
def calculate(df):
  pass
#讀取原始數(shù)據(jù)，將索引列去除
df = pd.read_excel('需求0621.xlsx',index_col=0)
#調(diào)用計(jì)算數(shù)據(jù)的函數(shù)
calculate(df)

先把整體思路寫好，再去想辦法計(jì)算每項(xiàng)數(shù)據(jù)

#計(jì)算累計(jì)和
    lst1 = []
    sum = 0
    for i in range(df.shape[0]):
        if i == 0:
            lst1.append(df['N'][i])
            sum += df['N'][i]
        else:
            sum += df['N'][i]
            lst1.append(sum)
    df['累計(jì)和'] = lst1
#計(jì)算回撤
    lst2 = []
    max = 0
    for i in range(df.shape[0]):
        if i == 0:
            lst2.append(0)
        elif df['累計(jì)和'][i] > max:
            max = df['累計(jì)和'][i]
            lst2.append(0)
        elif df['累計(jì)和'][i] < max:
            lst2.append(df['累計(jì)和'][i]-max)
        elif df['累計(jì)和'][i] == max:
            lst2.append(0)
    df['回撤'] = lst2
#計(jì)算連續(xù)正確的個(gè)數(shù)
    lst3 = []
    correct = 0
    for i in range(df.shape[0]):
        if df['N'][i] >= 0:
            correct += 1
            lst3.append(correct)
        else:
            lst3.append(0)
            correct = 0
    df['連續(xù)正確'] = lst3
#計(jì)算連續(xù)錯(cuò)誤的個(gè)數(shù)
    lst4 = []
    mistake = 0
    for i in range(df.shape[0]):
        if df['N'][i] < 0:
            mistake += 1
            lst4.append(mistake)
        else:
            lst4.append(0)
            mistake = 0
    df['連續(xù)錯(cuò)誤'] = lst4
#計(jì)算連續(xù)正確值
    lst5 = []
    for i in range(df.shape[0]):
        lst5.append('')
    right = 0
    for i in range(df.shape[0]):
        if df['連續(xù)正確'][i] != 0:
            right += df['N'][i]
        elif df['連續(xù)正確'][i] == 0 and right != 0:
            lst5[i-1] = right
            right = 0
    df['連續(xù)正確值'] = lst5
#計(jì)算連續(xù)錯(cuò)誤值
    lst6 = []
    for i in range(df.shape[0]):
        lst6.append('')
    wrong = 0
    for i in range(df.shape[0]):
        if df['連續(xù)錯(cuò)誤'][i] != 0:
            wrong += df['N'][i]
        elif df['連續(xù)錯(cuò)誤'][i] == 0 and wrong != 0:
            lst6[i-1] = wrong
            wrong = 0
    df['連續(xù)錯(cuò)誤值'] = lst6

最后將dataframe保存到excel

    df.to_excel('完成計(jì)算.xlsx')
    print('保持成功')

最終結(jié)果

技術(shù)總結(jié)

雖然已經(jīng)完成了要求計(jì)算出了所有的數(shù)據(jù)，但在寫代碼過(guò)程中計(jì)算的步驟都是基于python基礎(chǔ)語(yǔ)法實(shí)現(xiàn)的，對(duì)于pandas的使用還要只有通過(guò)大量的練習(xí)才能夠熟練的掌握

到此這篇關(guān)于利用Python實(shí)現(xiàn)簡(jiǎn)單的Excel統(tǒng)計(jì)函數(shù)的文章就介紹到這了,更多相關(guān)Python實(shí)現(xiàn)Excel統(tǒng)計(jì)函數(shù)內(nèi)容請(qǐng)搜索腳本之家以前的文章或繼續(xù)瀏覽下面的相關(guān)文章希望大家以后多多支持腳本之家！

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