def findall(pattern, string, flags=0):
    """Return a list of all non-overlapping matches in the string.
    If one or more capturing groups are present in the pattern, return
    a list of groups; this will be a list of tuples if the pattern
    has more than one group.
    Empty matches are included in the result."""
    return _compile(pattern, flags).findall(string)

import re
 
str = 'aabbabaabbaa'
#一個(gè)"."就是匹配除 \n (換行符)以外的任意一個(gè)字符
print(re.findall(r'a.b',str))#['aab', 'aab']
#*前面的字符出現(xiàn)0次或以上
print(re.findall(r'a*b',str))#['aab', 'b', 'ab', 'aab', 'b']
#貪婪，匹配從.*前面為開(kāi)始到后面為結(jié)束的所有內(nèi)容
print(re.findall(r'a.*b',str))#['aabbabaabb']
#非貪婪，遇到開(kāi)始和結(jié)束就進(jìn)行截取，因此截取多次符合的結(jié)果，中間沒(méi)有字符也會(huì)被截取
print(re.findall(r'a.*?b',str))#['aab', 'ab', 'aab']
#非貪婪，與上面一樣，只是與上面的相比多了一個(gè)括號(hào)，只保留括號(hào)的內(nèi)容
print(re.findall(r'a(.*?)b',str))#['a', '', 'a']
 
str = '''aabbab
         aabbaa
         bb'''#后面多加了2個(gè)b
#沒(méi)有把最后一個(gè)換行的aab算進(jìn)來(lái)
print(re.findall(r'a.*?b',str))#['aab', 'ab', 'aab']
#re.S不會(huì)對(duì)\n進(jìn)行中斷
print(re.findall(r'a.*?b',str,re.S))#['aab', 'ab', 'aab', 'aa\n         b']

str = 'aabbabaabbaa'

print(re.findall(r'a.b',str))
['aab', 'aab']

print(re.findall(r'a*b',str))
['aab', 'b', 'ab', 'aab', 'b']

print(re.findall(r'a.*b',str))
['aabbabaabb']

print(re.findall(r'a.*?b',str))
['aab', 'ab', 'aab']

print(re.findall(r'a(.*?)b',str))
['a', '', 'a']

str = '''aabbab
         aabbaa
         bb'''

print(re.findall(r'a.*?b',str))
['aab', 'ab', 'aab']

print(re.findall(r'a.*?b',str,re.S))
['aab', 'ab', 'aab', 'aa\n         b']