python實現(xiàn)的簡單RPG游戲流程實例
更新時間:2015年06月28日 15:35:35 作者:不吃皮蛋
這篇文章主要介紹了python實現(xiàn)的簡單RPG游戲流程,實例分析了Python實現(xiàn)RPG游戲流程的常用判定技巧,具有一定參考借鑒價值,需要的朋友可以參考下
本文實例講述了python實現(xiàn)的簡單RPG游戲流程。分享給大家供大家參考。具體如下:
#RPG
rpg = True
whp = 100
mahp = 100
hhp = 100
MHP = 10
def dgrnd () :
wa = raw_input ("What does Warrior do?")
ma = raw_input ("What does Mage do?")
ha = raw_input ("What does Healer do?")
if wa == "flame slash" :
print ("Warrior uses Flame Slash!")
MHP-20
elif wa == "Dragon Slash" and M == "Dragon" :
print ("Warrior used Dragon Slash!")
MHP-80
if wa == "Dragon" and M == "Troll" or M == "Goblin" :
print ("Warrior's attack did no damage!")
if ma == "icicle drop" :
print ("Mage used Icicle Drop")
MHP-15
mahp-10
whp-10
hhp-10
if ma == "flames of heck" :
MHP-75
mahp-50
wph-50
hhp-50
if ha == "heal warrior" :
print ("Healer Heals Warrior!")
whp + 20
if ha == "heal mage" :
print ("Healer Heals Mage!")
mahp + 20
if ha == "heal healer" :
print ("Healer Heals Healer!")
hhp + 20
if ha == "attack" :
print ("Healer Attacks!")
MHP - 5
print (M+"attacks!")
if M == "dragon" :
whp - 40
mahp - 40
hhp - 40
if M == "Troll" :
whp - 30
mahp - 30
hhp - 30
if M == "Goblin" :
whp - 20
mahp - 20
hhp -20
print ("Warrior has "+whp+" HP left, Mage has "+mahp+" HP left, and Healer has "+hhp+" HP left!")
if MHP == 0 :
print ("You defeated the "+M+" !")
print ("That is all I have built so far. Eventually, there will be more!")
print ("Thank You for Playing!!")
dgrnd ()
if rpg == True :
print ("This mode is not yet complete. It only contains a dungeon so far. I'm still working on the rest.")
#Dungeon
whp = 100
mahp = 100
hhp = 100
MHP = 10
M = "fail"
print ("You enter the dungeon")
rm = raw_input ("There are three passages. Do you take the first one, the second one, or the third one?")
if rm == 'one' :
M = 'Troll'
MHP = 80
print ("A "+M+" appears!")
if rm == 'two' :
M = 'Goblin'
MHP = 35
print ("A "+M+" appears!")
if rm == 'three' :
M = 'Dragon'
MHP = 120
print ("A "+M+" appears!")
while MHP > 0 :
dgrnd ()
希望本文所述對大家的Python程序設計有所幫助。
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